We factor the denominators
Factor x^2 - 16
x^2 - 4^2
We use a^2 - b^2 = (a+b)(a-b)
so x^2 - 4^2 = (x+4)(x-4)
Replace it in the given equation
Excluded values are the values that makes the denominator 0
we have (x-4) and (x+4) in the denominator
We set the denominator =0 and solve for x
x-4 =0
Add 4 on both sides
x= 4
x+4=0
subtract 4 onboth side
so x= -4
Excluded values are x=-4 and x=4
Answer:
Step-by-step explanation:
There are only 5 solutions:
x=-1
x=-1/3
x=0
x=1
x=8/3
See the graph
In blue: y=[x]²
In red : y=x+2(x-[x])
Sine, Cosine, Tangent
sine= opposite/ hypotenuse
cosine= adjacent/ hypotenuse
tangent= opposite/ adjacent.
a triangle with all three side labels you will be able to find them
My teacher taught me to make an imaginary decimal and 0 at the beginning of the number and then move the decimal to the end of the number... idk that may be the wrong way to do it but you can try :/
Answer:
<u>As per the graph we see:</u>
Domain is:
Range is: