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VashaNatasha [74]
3 years ago
10

Please help with this

Mathematics
1 answer:
Deffense [45]3 years ago
3 0

Answer:

Table A

Step-by-step explanation:

None of the numbers in the x values are repeating

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Four expressions are shown bellow
Irina18 [472]

Answer:

A

2(4x + 2)

and

D

8x + 4

Step-by-step explanation:

Because if you simplify the equation theb you get 8x+4 therefore D is equivalent to it. A is also equal to D which make it equivalent to the equation as well.

3 0
4 years ago
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I need help on my 3.3.6 Journal: Breakdown Ahead apex.
insens350 [35]

Answer:

pg. 1

teresa: use difference of 2 squares

rico: 6561 is not a perfect square

pg. 2

i think teresa is right and that 6561 can be broken down

problem 1: (x^4-81)^2=(x^2-9)^4=(x-3)^8

problem 2: a. false b. rico

pg. 3

problem 3: a. -1(3x+5)^2 b. teresa is right because it cant still be a perfect square trinomial while having a negative first term.

problem 4: a. (y+3)^2 b. teresa

pg. 4

problem 5: a. (x^n+y^n)(x^n-y^n) b. teresa

teresa got more right, rico is buying pizza

Step-by-step explanation:

apex

7 0
3 years ago
What is 3 times the power of 10
Paha777 [63]
I believe its 27 cause u have to multiply 3 times 3 which is 9, then 3 times 9 which is 27
8 0
4 years ago
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If alpha and beta are the roots of a quadratic polynomial 3x^2-6x-1 find the values of (Alpha-beta)
Murrr4er [49]

Answer:

Either -4\sqrt{6} or 4\sqrt{6}, depending on whether \alpha is larger than \beta.

Step-by-step explanation:

The two roots (might necessarily be distinct or real) of the quadratic equation

ax^{2} + bx + c = 0, where a, b, and c are constants and a\ne 0 are

  • \displaystyle x_1 = \frac{-b+\sqrt{\text{b^{2} - 4ac}}}{2a}, and
  • \displaystyle x_2 = \frac{-b-\sqrt{\text{b^{2} - 4ac}}}{2a}.

The difference between the two will be either:

x_1 - x_2 = 2\sqrt{b^{2} - 4ac} or

x_2 - x_1 = -2\sqrt{b^{2} - 4ac}.

For this question,

  • a = 3,
  • b = -6, and
  • c = -1.

x_1 - x_2 = 2\sqrt{(-6)^{2} - 4\times 3\times (-1)} = 4\sqrt{6}, or

x_1 - x_2 = -2\sqrt{(-6)^{2} - 4\times 3\times (-1)} = -4\sqrt{6}.

7 0
3 years ago
If y-18=14 what is the value of 3(y+5)?
svlad2 [7]
y-18=14\ \ \ /+18\\\\y-18+18=14+18\\\\y=32\\\\substitute\ to\ 3(y+5):\\\\3\cdot(32+5)=3\cdot37=111
4 0
3 years ago
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