Answer:
(-5,6)
Step-by-step explanation:
G(-5,4)=(x1,y1)
H(-5,8)=(x2, y2)
midpoint=?
now,
(x,y)= x1+x2/2 y1+y2/2
-5-5/2 4+8/2
-10/2 12/2
-5 6
therefore the co ordinates of midpoint are(-5,6)
<span>You are given a rectangular picture measuring 8 inches by 7 inches. Also, Alistair wants this to be framed and that the total area is 34 square inches. The width of the frame is x inches. To solve the dimension of the frame with value of x we have:
We have to assume that x here will be equal to all sides of the frame and so, using the area of the rectangle, we can model the equation like this:
A = LW (where A is the area, L is the length and W is the width)
36 = (8 - x)(7 - x)
36 = 56 - 8x - 7x + x</span>²
<span>x</span>² - 15x +20 = 0 → model of our equation and in quadratic form
x² - 15x + 20 = 0
using a calculator, x = 1.48 inches
<span>
3.Use the equation you created in part A to find the width of the picture frame</span>
Answer:
5.25
Step-by-step explanation:
If CD is perpendicular to AB, a right angle is formed by the perpendicular lines at the base of the triangle. If we know that AB is 3 we can divided that by two to use half the triangle and create a right trianle with a base of 1.5 (half of 3) a height of rad 3 now all we have to do is use P-Thags to find AC which is the hypotenuse. After doing 1.5 squared + rad 3 squared = ac squared you will get the answer of AC = 5.25
Answer:
N$12 576. 11
Step-by-step explanation:
Loss%=10%
S.P= N$11 480.50
C.P =?
Loss%=100(C.P - S.P)/C.P
10=100(C.P-11 480.50)/C.P
10C.P=100C.P - 1 148 050
1 148 050=100C.P - 10C.P
1 148 050=90C.P
C.P=N$12 576.11
