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Anit [1.1K]
2 years ago
13

1: How many total pounds of potatoes were rationed each week?

Mathematics
1 answer:
SashulF [63]2 years ago
6 0

Answer:

jk rjliukrulukurkd heeeey k37739

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UJ 1641"
Alekssandra [29.7K]

Answer:

t

Step-by-step explanation:

7 0
3 years ago
If no number can be used more than once, how many different 2-digit numbers can be formed from the digits 4, 6, and 8?
ikadub [295]

Answer:

Six.

46

48

64

68

84

86

Step-by-step explanation:

hoped this helped!

4 0
3 years ago
Answers for the homies that don’t wanna do the work edge 202
trapecia [35]
Wait what’s edge 202:|
7 0
3 years ago
John made this model to show \frac{4}{7}\times\frac{13}{9} 7 4 ​ × 9 13 ​ Using John's model, what is \frac{4}{7}\times\frac{13}
harkovskaia [24]

Answer:

\frac{4}{7}\times\frac{13}{9} = \frac{52}{63}

Step-by-step explanation:

Given

See attachment for model

Required

Determine \frac{4}{7}\times\frac{13}{9} from the model

The model is represented by:

\frac{4}{7}\times\frac{13}{9} = \frac{4}{7}\times\frac{9}{9} + \frac{4}{7}\times\frac{4}{9}

To get: \frac{4}{7}\times\frac{9}{9}, we consider the first partition

The number of shaded box is 63 ---- this represents the denominator

The total boxes shaded at the bottom is 36 ---- this represents the numerator

So, we have:

\frac{4}{7}\times\frac{9}{9} = \frac{36}{63}

To get: \frac{4}{7}\times\frac{9}{9}, we consider the first partition

The number of shaded box is 63 ---- this represents the denominator

The total boxes shaded at the bottom is 16 (do not count the gray boxes) ---- this represents the numerator

So, we have:

\frac{4}{7}\times\frac{4}{9} =\frac{16}{63}

The equation becomes:

\frac{4}{7}\times\frac{13}{9} = \frac{4}{7}\times\frac{9}{9} + \frac{4}{7}\times\frac{4}{9}

\frac{4}{7}\times\frac{13}{9} = \frac{36}{63} + \frac{16}{63}

\frac{4}{7}\times\frac{13}{9} = \frac{36+16}{63}

\frac{4}{7}\times\frac{13}{9} = \frac{52}{63}

5 0
3 years ago
Need help in statistics class
Bumek [7]
If you need help actually ask a question :l
6 0
3 years ago
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