All categories

2 years ago

Please first click on the image.

Mathematics

1 answer:

9966 [12]2 years ago

7 0

Let the figure number be x.

Then the equation will be:

There will be 3x circles in the figure number x.

So, number of circles in 50th figure will be

= 3(50)

= 3 × 50

= 150 circles

You might be interested in

Look at the image below.<br>I give Brainliest<br>Answer the questions.

olchik [2.2K]

Answer:you do every number plus 24 and that’s how you get it

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Pls help pls, i need this pls help

malfutka [58]

Answer:

Step-by-step explanation: a real one for the points

3 0

2 years ago

Telemarketing. the probability that a call will reach a live person is 0.2. the calls are independent. (a) a telemarketer places

Sergeeva-Olga [200]

Solution: Telemarketing. the probability that a call will reach a live person is 0.2. the calls are independent. (a) a telemarketer places 5 calls. what is the probability that none of them reaches a live person.

Answer: The given random experiment can be considered as binomial experiment with probability of success = 0.2 and number of trials = 5

Therefore, we have:

$n=5,p=0.2,q=(1-p)=1-0.2=0.8$

Let x be the number calls that reach to live person.

We have to find $P(x=0)$

Using the binomial probability distribution, we have:

$P(x=0)=\binom{5}{0}0.2^{0} (1-0.2)^{5-0}$

$=1 \times 1 \times 0.8^{5}$

$=0.3277$

Therefore, the probability that none of them reaches a live person is 0.3277

6 0

2 years ago

Hey could someone please help me with this really hard assignment is taking me forever. Thank you marking brainliest!

rewona [7]

Answer:

Exercise 1: The length of the unknown leg is 4 inches.

Exercise 3: The following straws can be used to construct the triangle: b) $3\,in$ , c) $4.5\,in$ , d) $6.5\,in$ , e) $10\,in$ , f) $13.5\,in$

Exercise 4: Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

Step-by-step explanation:

Exercise 1:

Let suppose that triangle represented in the figure is a right triangle, the length of the missing leg is determined by Pythagorean Theorem:

$y = \sqrt{l^{2}-x^{2}}$ (1)

Where:

$l$ - Hypotenuse, in inches.

$x$ - Known leg, in inches.

$y$ - Unknown leg, in inches.

If we know that $l = 11\,in$ and $x = 10\,in$ , then the length of the unknown leg is:

$y = \sqrt{21}$

Since 4 is the least whole number closest to $\sqrt{21}$ , then we conclude that the length of the unknown leg is 4 inches.

Exercise 3:

The range of possible lengths for the missing side of the triangle is represented by the following simultaneous inequality:

$x + y > l > x-y$ (2)

Where:

$x$ - Greater side, in inches.

$y$ - Lesser side, in inches.

$l$ - Missing side, in inches.

If we know that $x = 8\,in$ and $y = 6\,in$ , then we have the following range of missing sides:

$14\,in > l > 2\,in$

The following straws can be used to construct the triangle: b) $3\,in$ , c) $4.5\,in$ , d) $6.5\,in$ , e) $10\,in$ , f) $13.5\,in$

Exercise 4:

Let check each pair to determine possible constructions by means of the inequality used in Exercise 3:

(i) $x = 4\,in, y = 2\,in$

$6\,in>l>2\,in$

Possible choices: 5 inches.

(ii) $x = 5\,in, y = 2\,in$

$7\,in > l > 3\,in$

Possible choices: 4 inches, 6 inches.

(iii) $x = 6\,in, y = 2\,in$

$8\,in > l > 4\,in$

Possible choices: 5 inches, 6 inches.

(iv) $x = 10\,in, y = 2\,in$

$12\,in > l > 8\,in$

Possible choices: None.

(v) $x = 5\,in, y = 4\,in$

$9\,in > l > 1\,in$

Possible choices: 2 inches, 6 inches.

(vi) $x = 6\,in, y = 4\,in$

$10\,in > l > 2\,in$

Possible choices: 5 inches.

(vii) $x = 10\,in, y = 4\,in$

$14\,in > l > 6\,in$

Possible choices: None.

(viii) $x = 6\,in, y = 5\,in$

$11\,in > l > 1\,in$

Possible choices: 2 inches, 4 inches, 10 inches.

(ix) $x = 10\,in, y = 5\,in$

$15\,in > l > 5\,in$

Possible choices: 6 inches.

(x) $x = 10\,in, y = 6\,in$

$16\,in > l > 4\,in$

Possible choices: 5 inches.

Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

7 0

2 years ago

Read 2 more answers

A rectangle or piece of paper has a width is 3 inches less than its link it is cut in half along a diagonal to create two congru

kolezko [41]

The length and width of the rectangle is 11 in and 8 in respectively.

Step-by-step explanation:

Given,

The width of a rectangle is 3 in less than the length.

The area of each congruent right angle triangle = 44 in²

To find the length and width of the rectangle.

Formula

The area of a triangle with b base and h as height = $\frac{1}{2}$ bh

Now,

Let, the width = x and the length = x+3.

Here, for the triangle, width will be its base and length will be its height.

According to the problem,

$\frac{1}{2}$ ×(x+3)×x = 44

or, $x^{2} +3x = 88$

or, $x^{2} +3x-88 = 0$

or, $x^{2}$ +(11-8)x-88 = 0

or, $x^{2}$ +11x-8x-88 =0

or, x(x+11)-8(x+11) = 0

or, (x+11)(x-8) = 0

So, x = 8 ( x≠-11, the length or width could no be negative)

Hence,

Width = 8 in and length = 8+3 = 11 in

3 0

2 years ago