A function assigns the values. The value of (p·p)(x) is x⁴ + 10x³ + 30x² + 25x.
<h3>What is a Function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
Given p(x)= x²+5x, therefore, the value of (p·p)(x) can be written as,
(p·p)(x) = p(p(x))
= (x²+5x)²+5(x²+5x)
= x⁴ + 25x² + 10x³ + 5x² + 25x
= x⁴ + 10x³ + 30x² + 25x
Hence, the value of (p·p)(x) is x⁴ + 10x³ + 30x² + 25x.
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The domain { x | x = -5 , -3 , 1 , 2 , 6}
D) 36
So q is equal to -12 and P divided by Q will be equal to -3
but since you know Q you replace it with -12 and now it's gonna be P divided by -12 equal to -3
move -12 to the other side by multiplying -12 to both sides so you cancel out the -12 under P and you get to isolate P
-3 times -12 will be +36 because the two negative signs cancel out
Answer:
15 (3+1)
Step-by-step explanation:
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