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Scilla [17]
3 years ago
11

How much energy is required to raise the temperature of 3 kg of iron from 20°

Chemistry
1 answer:
Vinvika [58]3 years ago
8 0

Answer:

Option C (6750 J) is the appropriate response.

Explanation:

The given values are:

Mass of iron,

m = 3 kg

Specific heat capacity,

c_A = 0.450

Temperature,

T = 25-20

  = 5^{\circ}C

Now,

⇒  Q=mc_A T

On substituting the values, we get

⇒      =3\times 0.450\times 5

⇒      =6.75

i.e,

⇒      =6750 \ J

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6 0
3 years ago
A particular reactant decomposes with a half‑life of 109 s when its initial concentration is 0.280 M. The same reactant decompos
Sophie [7]

Answer:

The order of reaction is 2.

Rate constant is 0.0328 (M s)⁻¹

Explanation:

The rate of a reaction is inversely proportional to the time taken for the reaction.

As we are decreasing the concentration of the reactant the half life is increasing.

a) For zero order reaction: the half life is directly proportional to initial concentration of reactant

b) for first order reaction: the half life is independent of the initial concentration.

c) higher order reaction: The relation between half life and rate of reaction is:

Rate = \frac{1}{k[A_{0}]^{(n-1)}}

Half life =K\frac{1}{[A_{0}]^{(n-1)} }

\frac{(halflife_{1})}{(halflife_{2})}=\frac{[A_{2}]^{(n-1)}}{[A_{1}]^{(n-1)} }

where n = order of reaction

Putting values

\frac{109}{231}=\frac{[0.132]^{(n-1)}}{[0.280]^{(n-1)}}

0.472=(0.472)^{(n-1)}

Hence n = 2

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Putting values

231=\frac{1}{K(0.132)}

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4 0
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