Question

How does a sample of water at 38 °C compare to a sample of water at 295 K?

Answer 1

Converting the temperature, 295 K from Kelvin to Celsius scale:

$295 K - 273 = 22^{0} C$

Water has a boiling point of $100^{0}C$ and a melting point of $0^{0} C$

When we compare water at two different temperatures, $22^{0}C and 38^{0}C$ we can say that water is in liquid form at both these temperatures as both of them are quite below the boiling temperature and above the melting temperature.

The temperature difference between water at the given two temperatures = $38^{0}C - 22^{0}C = 16^{0}C$

Water at $38^{0}C$ is at a higher temperature and so is warmer than water at a lower temperature of $22^{0}C (or 295 K)$.