Answer:
7x(3-5a)
Step-by-step explanation:
21-35a =
to find a minimum common multiply you have to rationalize the number with the same numer, and this number must be a whole, this will help you to write the expression easier, if you notice that 21 and 35 are familiar of 7, then you can find a common factor, to multiply your expression
Answer:
D. 22.5 sq. un.
Step-by-step explanation:
W divides BU so that there is a ratio of 1;2 meaning that there are 3 parts.
That means that 3 parts is BUV; we know that one of those parts is 4.5 sq. un. so 4.5*3=13.5 sq. un. - Also 4.5*2=9 to get WUV
V is the midpoint of the line BS so that means that BUV and UVS are equal
we know that BUV is 13.5 so we multiply that by 2 to get the whole triangle
=27
The last step is to get rid of BVW which we know is 4.5
27-4.5=22.5
Answer:
She earned $20 in tips.
Step-by-step explanation:
First, you need to work out how much pay she'd get for 12 hours work:
12 x $11.25 = $135 for 12 hours work
Then, find out 2/5 of $11.25 to find out how much she would get for the 2/5 of an hour she worked:
2/5 of $11.25 = $4.50
Add both these sums together to get her total pay for hours worked:
$135 + $4.50 = $139.50
Subtract that sum from her total pay to find out how much money she earned in tips:
$159.50 - $139.50 = <u>$20</u>
Answer:
The best estimate is greater than 1/2 but less than 3/4
Step-by-step explanation:
If you multiply 1/4 by 3/3 (which is also 1), you can change the denominator without changing the value. So 1/4 is equal to 3/12.
Since keith has 11/12 hours to play, and he has already played 3/12 hours, subtract 3/12 from 11/12 to get 8/12 hours. This is how much time he has left to play.
If you simplify 8/12 hours, you get 2/3 hours.
So the best estimate would be: greater than 1/2 but less than 3/4.
If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
