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matrenka [14]
3 years ago
11

PLEASE HELP!!! 2 + x + x + x = 4x The equation has infinite solutions right?

Mathematics
1 answer:
zzz [600]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

x is an irrational number which is infinite

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True or false:<br> the following equation is in standard form. <br> (x - 4.2)^2 - 3 = 0
natita [175]

Answer:

false

Step-by-step explanation:

standard form cannot contain fractions or decimals

3 0
2 years ago
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sammy [17]

Answer:Its N and Q

Step-by-step explanation:

3 0
2 years ago
If g(x) = 10 - 2x then which of the following is the value of g(7)?
slega [8]

Answer:

g(7)= -4

Step-by-step explanation:

10-2(7)

10-14

=-4

4 0
3 years ago
Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,4​) and passes through the point ​(−7​,0). Write the function
olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

a=-\frac{1}{4}

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

5 0
3 years ago
(-3,600,000,000)x(0.00000824)
Nadusha1986 [10]
-29664 is the correct answer. This mostly deals with the zeros and crossing them off
8 0
3 years ago
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