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oee [108]
3 years ago
3

Explain the difference between finding the volume of this right rectangular prism with whole unit cubes and with 1/2 -unit cubes

.
Pls do not give me a bad answer

Mathematics
1 answer:
pogonyaev3 years ago
5 0

Finding volume by multiplying

Finding volume with unit cubes

you take base one and mulitiply it by the number its beside. then multiply by the height

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Please help! I’m on a timer :/
weqwewe [10]

If you want to find out how Addision paid each month, you have to have 36, then divide 36 by 12, and the answer will give you 3. So Addison paid $3 every month.

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Nate

4 0
3 years ago
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Finals are​ over, and you are moving back home for the summer. You need to rent a truck to move your possessions from the colleg
rewona [7]
In short you just multiply 0.480.48 by the amount of miles you drive add that to 24.9024.90 and you get you total
for example: if you take the first company if you drive 200 miles per day it will cost you 24.9024.90 with an extra 96.096 wich will add up to 120.99849 in total per day 
5 0
3 years ago
Use the equation d=z–9 to find the value of d when z=10.<br><br> d=
denis23 [38]

Step-by-step explanation:

d = z - 9

d = 10 - 9  ----> substitute

d = 1

5 0
3 years ago
Find the direction cosines and direction angles of the vector. (Give the direction angles correct to the nearest degree.) 5, 1,
Dahasolnce [82]

Answer:

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

Step-by-step explanation:

For a given vector a = ai + aj + ak, its direction cosines are the cosines of the angles which it makes with the x, y and z axes.

If a makes angles α, β, and γ (which are the direction angles) with the x, y and z axes respectively, then its direction cosines are: cos α, cos β and cos γ in the x, y and z axes respectively.

Where;

cos α = \frac{a . i}{|a| . |i|}               ---------------------(i)

cos β = \frac{a.j}{|a||j|}               ---------------------(ii)

cos γ = \frac{a.k}{|a|.|k|}             ----------------------(iii)

<em>And from these we can get the direction angles as follows;</em>

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

Now to the question:

Let the given vector be

a = 5i + j + 4k

a . i =  (5i + j + 4k) . (i)

a . i = 5         [a.i <em>is just the x component of the vector</em>]

a . j = 1            [<em>the y component of the vector</em>]

a . k = 4          [<em>the z component of the vector</em>]

<em>Also</em>

|a|. |i| = |a|. |j| = |a|. |k| = |a|           [since |i| = |j| = |k| = 1]

|a| = \sqrt{5^2 + 1^2 + 4^2}

|a| = \sqrt{25 + 1 + 16}

|a| = \sqrt{42}

Now substitute these values into equations (i) - (iii) to get the direction cosines. i.e

cos α = \frac{5}{\sqrt{42} }

cos β =  \frac{1}{\sqrt{42} }              

cos γ =  \frac{4}{\sqrt{42} }

From the value, now find the direction angles as follows;

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

α =  cos⁻¹ ( \frac{5}{\sqrt{42} } )

α =  cos⁻¹ (\frac{5}{6.481} )

α =  cos⁻¹ (0.7715)

α = 39.51

α = 40°

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

β = cos⁻¹ ( \frac{1}{\sqrt{42} } )

β = cos⁻¹ ( \frac{1}{6.481 } )

β = cos⁻¹ ( 0.1543 )

β = 81.12

β = 81°

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

γ = cos⁻¹ (\frac{4}{\sqrt{42} })

γ = cos⁻¹ (\frac{4}{6.481})

γ = cos⁻¹ (0.6172)

γ = 51.89

γ = 52°

<u>Conclusion:</u>

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

3 0
3 years ago
Find the coordinates of the points of intersection of the graphs with coordinate axes: y=− 1/4 x+2
bearhunter [10]

Answer:


Step-by-step explanation:

Here, you can use a simple formula.

To find the point of intersection you just put x=0 or y=0.

Because, if a graph intersects x-axis, then at this point  y=0

Similarly, if a graph intersects y-axis, then at this point  x=0


So, for our given line.

y=-1/4 x +2

when , x=0 , y=-1/4 (0)+2=2

So, the graph intersects y-axis at   y=2


when , y=0 ,

then    0=-1/4 x+2

       or, 1/4 x=2

       or, x=8    [multiplying by  4]

So, the graph intersects x-axis at   x=8

3 0
3 years ago
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