Answer:
a) C. The random variable is discrete. The possible values are xequals0, 1, 2,....
b) B. The random variable is continuous. The possible values are x greater than or equals 0.
Step-by-step explanation:
Discrete variables are countable in a finite amount of time. Continuous variables can be infinitely many. They rather assume values in a range.
<u><em>(a) Is the number of hits to a Web site in a day discrete or continuous? </em></u>
C. The random variable is discrete. The possible values are x equals 0, 1, 2,....
<u><em>(b) Is the weight of a Upper T dash bone steak discrete or continuous?</em></u>
B. The random variable is continuous. The possible values are x greater than or equals 0.
Answer:
1=125
2=55
3=55
4=125
5=125
6=55
7=55
8=125
Step-by-step explanation:
Answer:
(6, -4)
Step-by-step explanation:
The ice cream shop should be between the school and hospital.
Answer:
for 12-8: 33.33
or
for 8-4: 50
or
for 12-4: 66.67
Step-by-step explanation:
Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027