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3 years ago

The molar mass of C6H6 78.11g 78.108amu

Chemistry

2 answers:

andrezito [222]3 years ago

4 0

Answer:

The answer is 78.108amu

lorasvet [3.4K]3 years ago

3 0

Answer:

78.11 g is the right Answer!

Explanation:

Hope it Helps!

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Which is a nonmetal that becomes isoelectronic with argon<br> when it forms its most common ion?

mrs_skeptik [129]

Answer:sulfur

Explanation:

6 0

3 years ago

CK-12 Boyle and Charles's Laws if Mrs. Pa pe prepares 12.8 L of laughing gas at 100.0 k Pa and -108 °C and then she force s the

nirvana33 [79]

Answer:

The answer to your question is P2 = 2676.6 kPa

Explanation:

Data

Volume 1 = V1 = 12.8 L Volume 2 = V2 = 855 ml

Temperature 1 = T1 = -108°C Temperature 2 = 22°C

Pressure 1 = P1 = 100 kPa Pressure 2 = P2 = ?

Process

- To solve this problem use the Combined gas law.

P1V1/T1 = P2V2/T2

-Solve for P2

P2 = P1V1T2 / T1V2

- Convert temperature to °K

T1 = -108 + 273 = 165°K

T2 = 22 + 273 = 295°K

- Convert volume 2 to liters

1000 ml -------------------- 1 l

855 ml -------------------- x

x = (855 x 1) / 1000

x = 0.855 l

-Substitution

P2 = (12.8 x 100 x 295) / (165 x 0.855)

-Simplification

P2 = 377600 / 141.075

-Result

P2 = 2676.6 kPa

3 0

3 years ago

Select the correct answer.

Ilya [14]

Answer:

C is the answer hope I helped you have a good day by

3 0

3 years ago

An element from the periodic table is shown below. What can you determine about the number of protons, neutrons, and electrons o

Musya8 [376]

Answer:

They are all the same = 8

Explanation:

Since the symbol of that atom is not give, we can infer from the given number the nature and kind of element we are dealing with.

The number 15.999 rounded up to 16 is the atomic weight of the atom also called the mass number.

Although not peculiar enough, we are certain that this atom is Oxygen.

On the periodic table, elements are arranged based on their atomic numbers.

Atomic number of oxygen = 8 = number of protons

For every neutral atom on the periodic table, the number of protons and electrons are the same

Atomic number of oxygen = number of protons = number of electrons = 8

Number of neutrons = Mass number - atomic number = 16 - 8 = 8

4 0

4 years ago

An ideal gas is brought through an isothermal compression process. The 3.00 mol of gas goes from an initial volume of 261.6×10−6

Eduardwww [97]

Answer : The temperature and the final pressure of the gas is, 586.83 K and $1.046\times 10^{9}atm$ respectively.

Explanation : Given,

Initial volume of gas = $261.6\times 10^{-6}m^3$

Final volume of the gas = $138.2\times 10^{-6}m^3$

Heat released = -9340 J

First we have to calculate the temperature of the gas.

According to the question, this is the case of isothermal reversible compression of gas.

As per first law of thermodynamic,

$\Delta U=q+w$

where,

$\Delta U$ = internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

$q=-w$

Thus, w = -q = 9340 J

The expression used for work done will be,

$w=nRT\ln (\frac{V_2}{V_1})$

where,

w = work done = 9340 J

n = number of moles of gas = 3 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = ?

$V_1$ = initial volume of gas

$V_2$ = final volume of gas

Now put all the given values in the above formula, we get the temperature of the gas.

$9340J=3mole\times 8.314J/moleK\times T\times \ln (\frac{261.6\times 10^{-6}m^3}{138.2\times 10^{-6}m^3})$

$T=586.83K$

Now we have to calculate the final pressure of the gas by using ideal gas equation.

$PV=nRT$

where,

P = final pressure of gas = ?

V = final volume of gas = $138.2\times 10^{-6}m^3=138.2\times 10^{-9}L$

T = temperature of gas = 586.83 K

n = number of moles of gas = 3 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get:

$P\times (138.2\times 10^{-9}L)=3mole\times (0.0821L.atm/mole.K)\times (586.83K)$

$P=1.046\times 10^{9}atm$

Therefore, the temperature and the final pressure of the gas is, 586.83 K and $1.046\times 10^{9}atm$ respectively.

6 0

3 years ago