ANs:
[A] = [B] = 0.094 M
The following reaction was monitored as a function of time:
AB --> A + B
A plot of 1/[AB] versus time is a straight line with slope, K = 5.5×10^−2 M * s.
Now,
![\frac{1}{[AB]} = \frac{1}{[AB_{0} ]} + kT \\ \\ \frac{1}{[AB]} = \frac{1}{0.210} + (5.5* 10^{-2})*70 sec \\ \\ \\ \[AB] = 0.116](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%5BAB%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B%5BAB_%7B0%7D%20%5D%7D%20%2B%20kT%20%5C%5C%20%5C%5C%20%5Cfrac%7B1%7D%7B%5BAB%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B0.210%7D%20%2B%20%285.5%2A%2010%5E%7B-2%7D%29%2A70%20sec%20%5C%5C%20%5C%5C%20%5C%5C%20%5C%5BAB%5D%20%3D%200.116)
<span>Now, Since at 70 s, [AB] = 0.116 M,
then amount of AB lost: </span>
<span>0.210 M - 0.116 M = 0.094 M
</span>
Now, according to the stoichiometry of the reaction,
<span>AB : A : B = 1 : 1 : 1,
</span>
<span>so both [A] and [B] gained the same number of moles and thus have same concentration, as [AB] lost.
So, [A] = [B] = 0.094 M after 70 s.</span>
Answer:
C. Because my teacher said so
Hope this helps :)
The empirical formula is 
.
<u>Explanation:</u>
Putrescine has the elements like Carbon, Nitrogen and Hydrogen present in them. So in order to determine the empirical formula, we first have to find the number of moles present in the putrescine. As the percentage of C, H and N present in the chemical is given as 54.50%, 13.73% and 31.77%, we assume that 100 g of Putrescine is taken as sample.
Then the mass of C, H and N present in Putrescine will be 54.50 g, 13.73 g and 31.77 g. We know that the molar mass of C is 12 g/mol, H is 1 g/mol and N is 14 g/mol. So divide the mass with the molar mass of the respective elements to determine the number of moles of these elements present in the sample.
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Similarly, the number of moles of H and N present is determined.
Then the empirical formula can be determined by dividing the number of moles of all elements with the least number of moles that is 2.27.
So, the empirical formula is .
Answer:
Option B
Explanation:
Remember that the products are on the right side of a chemical equation while the reactant is on the left.
In this case we have...
C2H6 + O2 ⇒ CO2 + H2O
Since C2H6 and O2 are on the left side that would mean they're the reactants, while CO2 + H2O are the products. Which means your answer is option B or "C2H6 + O2 are the reactants, CO2 + H2O are the products."
Hope this helps.
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Hey There!</h2><h2>
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Answer:</h2>
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London Dispersion force or Van de waals force is a temporary attractive force which are the weakest and occur between nonpolar noble gases and same charges. This force is weaker because they have more electrons that are farther from the nucleus and are able to move around easier.
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Dipole force is present between the polar molecules. Polar molecules are those molecules which have slightly negative and slightly positive charge. Dipole-dipole forces are attractive forces between the positive end of one polar molecule and the negative end of another polar molecule.
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It is a special type of dipole force present between polar molecules, it is formed between Hydrogen atom which forms positive ion, and the other negative ion. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom. The hydrogen bond is one of the strongest intermolecular attractions, but weaker than a covalent or an ionic bond.
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