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Bogdan [553]
3 years ago
11

In Belize City, on a cloudy day the temperature is 24 degrees Celsius. This is equal to how much in Fahrenheit. *

Chemistry
1 answer:
MAVERICK [17]3 years ago
7 0
The answer is 75.2. Hope this helps! Plus here is proof from a calculators calculations.

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A hockey puck moving at 28 m/s is caught by an 80.00 kg man who was at rest the man and puck moved together after the collision.
hodyreva [135]

Answer: The final velocity of both man and hokey puck will be 0.056 m/s.

Explanation: We are given 2 objects and are undergoing collision. The final velocity of both the objects is same. To calculate the final velocity, we will use the principle of conservation of momentum.

This principle states that when the objects that are colliding makes up a system, then the total momentum will remain constant if no external force is applied on it.

Sum of Initial momentum of two objects = Sum of Final momentum of the two objects

Mathematically,

m_1u_1+m_2u_2=m_1v_1+m_2v_2     ...(1)

where,

m_1,u_1\text{ and }v_1 are the mass, initial velocity and final velocity of the first object.

m_2,u_2\text{ and }v_2 are the mass, initial velocity and final velocity of the second object.

Here, man and hockey puck are moving together after the collision, so their final velocities will be same.

m_1=80.00kg\\m_2=0.16kg\\u_1=0m/s\\u_2=28m/s\\v_1=v_2=V=?m/s

Putting values in equation 1, we get:

80(0)+0.16(28)=(0.80+0.16)V

V=0.056m/s

The final velocity of man and hockey puck is 0.056 m/s.

6 0
3 years ago
Read 2 more answers
Potassium chloride and water for from the reaction of an acid base THEREFORE KCI is a .....
nordsb [41]
It is a salt and salt salt and
4 0
3 years ago
Write a chemical equation for solid cadmium hydrogen carbonate decomposing to yield solid cadmium carbonate, water, and carbon d
madreJ [45]

Answer:

Cd(HCO₃)₂ (s) ⇒ CdCO₃ (s) + H₂O (l) + CO₂ (g)

Explanation:

Cadmium hydrogen carbonate = Cd(HCO₃)₂ (solid)

Cadmium carbonate = CdCO₃ (solid)

Water = H₂O (liquid)

Carbon dioxide = CO₂ (gas)

Skeleton equation: Cd(HCO₃)₂ (s) ⇒ CdCO₃ (s) + H₂O (l) + CO₂ (g)

This is already balanced.

6 0
3 years ago
What is oxidized and what is reduced <br> C2H4 + 2O2 → 2CO + 2H2O<br> C2H4 + 3O2 → 2CO2 + 2H2O
Anika [276]

C2H4 is oxidized and O2 is reduced in both reactions.

<h3>What is oxidation/reduction?</h3>

Oxidation is defined in several ways. Some of the definitions are:

  1. The addition of oxygen or removal of hydrogen
  2. Increase in the oxidation number of atoms
  3. Addition of electronegative or the removal of electropositive elements

Reduction, on the other hand, is defined as:

  1. Removal of oxygen or addition of hydrogen
  2. Decrease in the oxidation number of atoms
  3. Addition of electropositive elements or the removal of electronegative elements.

In the two reactions, oxygen is being added to C2H4. Thus, C2H4 is being oxidized.

The oxidizing agent is O2. In oxidation reactions, the oxidizing agents usually get reduced. Thus, O2 is reduced in both reactions.

More on oxidation and reduction can be found here: brainly.com/question/3867774

#SPJ1

7 0
2 years ago
Consider the equilibrium
Kamila [148]

Answer:

The answers are in the explanation

Explanation:

For the equilibrium:

B(aq) + H₂O(l) ⇌ HB⁺(aq) + OH⁻(aq).

By LeChatelier's principle, the increase in the concentration of a reactant (for example) at equilibrium will change the system counteracting the increasing producing more product.

Thus,

A) Will the equilibrium constant for the reaction increase, decrease, or stay the same? Why? .

The equilibrium constant is a thermodynamic constant that stay the same with the addition of a compound.

B) Will the concentration of HB⁺(aq) increase, decrease, or stay the same? Why?

By LeChatelier's principle, the addition of B will induce the formation of more HB⁺(aq) increasing the concentration.

C) Will the pH of the solution increase, decrease, or stay the same? Why?

As the addition of B induce the increasing of OH⁻, the pH of the solution will increase.

I hope it helps!

7 0
4 years ago
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