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2 years ago

What is oxidized and what is reduced C2H4 + 2O2 → 2CO + 2H2O C2H4 + 3O2 → 2CO2 + 2H2O

Chemistry

1 answer:

Anika [276]2 years ago

7 0

C2H4 is oxidized and O2 is reduced in both reactions.

<h3>What is oxidation/reduction?</h3>

Oxidation is defined in several ways. Some of the definitions are:

The addition of oxygen or removal of hydrogen
Increase in the oxidation number of atoms
Addition of electronegative or the removal of electropositive elements

Reduction, on the other hand, is defined as:

Removal of oxygen or addition of hydrogen
Decrease in the oxidation number of atoms
Addition of electropositive elements or the removal of electronegative elements.

In the two reactions, oxygen is being added to C2H4. Thus, C2H4 is being oxidized.

The oxidizing agent is O2. In oxidation reactions, the oxidizing agents usually get reduced. Thus, O2 is reduced in both reactions.

More on oxidation and reduction can be found here: brainly.com/question/3867774

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3 years ago

What are three similarities between biotic and abiotic factors?

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3 years ago

According to the aufbau principle,_____.

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Answer:

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3 years ago

Read 2 more answers

How many particles are present in 12.47 grams of NaCl

liq [111]

Answer:

1.26*10²³ particles are present in 12.47 grams of NaCl

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023 * 10²³ particles per mole. The Avogadro number applies to any substance.

So, first of all you must know the amount of moles that represent 12.47 grams of NaCl. For that it is necessary to know the molar mass.

You know:

Na: 23 g/mole
Cl: 35.45 g/mole

So the molar mass of NaCl is: 23 g/mole + 35.45 g/mole= 58.45 g/mole

Now you apply a rule of three as follows: if 58.45 grams are present in 1 mole of NaCl, 12.47 grams in how many moles will they be?

$moles=\frac{12.47 grams*1 mole}{58.45 grams}$

moles= 0.21

You apply a rule of three again, knowing Avogadro's number: if in 1 mole of NaCl there are 6,023 * 10²³ particles, in 0.21 moles how many particles are there?

$number of particles=\frac{0.21 moles*6.023*10^{23} }{1 mole}$

number of particles= 1.26*10²³

1.26*10²³ particles are present in 12.47 grams of NaCl

5 0

3 years ago

In order to prepare a 0.523 m aqueous solution of potassium iodide, how many grams of potassium iodide must be added to 2.00kg o

Lerok [7]

M = amount of the solute / mass of the solvent

0.523 = x / 2.00

x = 0.523 * 2.00

x = 1,046 moles

molar mass KI = 166.0028 g/mol

Mass = 1,046 * 166.0028

Mass ≈ 173.63 g

hope this helps!

6 0

3 years ago