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3 years ago

Which two expenses are considered variable expenses?

Mathematics

1 answer:

marusya05 [52]3 years ago

6 0

Answer:

Step-by-step explanation:

Examples of variable costs are sales commissions, direct labor costs, cost of raw materials used in production, and utility costs.

Secondly, what is fixed expenses and variable expenses? Fixed expenses cost the same amount each month and are usually paid on a regular basis. One example of a fixed expense is rent. Variable expenses can change based on the day, week or month. For instance, medical costs can be categorized as a variable expense.

Correspondingly, what are considered variable expenses?

Variable expenses, also called variable costs, are expenses that can change over time. Variable expenses differ from fixed expenses, such as your mortgage or rent, that remain the same throughout the term of your loan or lease.

What are the 3 types of expenses?

There are three major types of expenses we all pay: fixed, variable, and periodic.

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Simplify 3/4(1/2x + 4) + 1/2(x − 1)

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3/4(1/2x + 4) + 1/2(x − 1)

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Use properties to rewrite the given equation. Which equations have the same solution as 3/5x +2/3 + x = 1/2– 1/5x? Check all tha

vodomira [7]

we have

$\frac{3}{5}x+ \frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x$

Combine like terms in both sides

$(\frac{3}{5}x+ x)+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

we know that

$(\frac{3}{5}x+ x)=(\frac{3}{5}x+ \frac{5}{5}x)=\frac{8}{5}x$

substitute in the expression above

$\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$ -----> equation A

Multiply equation A by $5*3*2=30$ both sides

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Group terms that contain the same variable, and move the constant to the opposite side of the equation

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Solve for x

$x=-\frac{5}{54} =-0.09$

We are going to proceed to verify each case to determine the solution.

Case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

the case a) is equal to the equation A

the case a) have the same solution that the given equation

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Combine like terms in left side

$(18x+30x)+20=15-6x$

$(48x)+20=15-6x$

the case b) is equal to the equation B

the case b) have the same solution that the given equation

Case c) $18x+20+x=15-6x$

Combine like terms in left side

$(18x+x)+20=15-6x$

$(19x)+20=15-6x$

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$-0.20\neq -0.09$

therefore

the case c) not have the same solution that the given equation

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Combine like terms in left side

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the case d) have the same solution that the given equation

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Combine like terms in left side

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therefore

the case e) not have the same solution that the given equation

therefore

the answer is

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case b) $18x+20+30x=15-6x$

case d) $24x+30x=-5$

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