The integral which expresses the area of the region bounded by y = ¹/₂x - 2 and y = ∛x is; ∫⁸₀((x^(1/3)) - ¹/₂x + 2
<h3>How to integrate between two curves?</h3>
We are given the functions as;
y = ¹/₂x - 2
y = ∛x
Now, from the graph the coordinate of the point where both curves intersect is at; (8, 2)
Thus, the x-coordinate here is x = 8
∛x - (¹/₂x - 2)
∛x - ¹/₂x + 2
Similarly, another point of intersection of both curves is at the coordinate (0, -2). Thus, the x-coordinate here is; x = 0
Thus, the integral which expresses the area of the region bounded by y = ¹/₂x - 2 and y = ∛x is; ∫⁸₀((x^(1/3)) - ¹/₂x + 2
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