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3 years ago

The amount that two groups of students spent on snacks in one day is shown in the dot plots below.

Mathematics

1 answer:

Ymorist [56]3 years ago

5 0

Answer:

1. The mean for Group A is less than the mean for Group B

2. The median for Group A is less than the median for Group B.

3. The mode for Group A is less than the mode for Group B.

Step-by-step explanation:

1. To find the mean for Group A, you use the formula: Total sum/Total frequency.

To find the total sum, you multiply the frequency(how many times the given number is repeated) with the given numbers.

0 × 0 = 0

1 × 5 = 5

2 × 4 = 8

3 × 1 = 3

4 × 0 = 0

5 × 0 = 0

Total Sum: 5 + 8 + 3 = 16

Total frequency: 5 + 4+ 1 = 10

$\frac{16}{10}$ = 1.6

To find the mean for Group B, you repeat everything above.

0 × 0 = 0

1 × 3 = 3

2 × 2 = 4

3 × 4 = 12

4 × 0 = 0

5 × 1 = 5

Total Sum: 3 + 4 + 12 + 5 = 24

Total frequency: 3 + 2 + 4 + 1 = 10

$\frac{24}{10}$ = 2.4

2. I can't explain it but I'm certain that it is correct.

3. The most repeated number for Group A is 1, it is repeated 5 times, while the most repeated number in Group B is 3, it is repeated 4 times.

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For each inequality, draw a number line and show all points that satisfy it. a 0

OleMash [197]

Where’s the question

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2 years ago

21. For the following exercises, use the descriptions of each pair of lines given below to find the slopes of Line 1 and Line 2.

dybincka [34]

Answer:

The given lines are perpendicular.

Step-by-step explanation:

In the question, two lines are given as line 1 passes through (1,7) and (5,5). Whereas, line 2 passes through (-1,-3) and (1,1).

It is required to find the slope of given lines and figure out whether they are perpendicular, parallel or neither.

To solve this question, first find the slope of both lines. Check if their product is equal to -1, then they are perpendicular. If the slopes are equal the lines are parallel.

Step 1 of 2

Find the slope of first line.

$\begin{aligned}m_{1} &=\frac{5-7}{5-1} \\m_{1} &=\frac{-2}{4} \\m_{1} &=-\frac{1}{2}\end{aligned}$

Step 2 of 2

Find the slope of first line.

$\begin{aligned}&m_{2}=\frac{1-(-3)}{1-(-1)} \\&m_{2}=\frac{4}{2} \\&m_{2}=2\end{aligned}$

And

$\begin{aligned}&m_{1} m_{2}=-\frac{1}{2}(2) \\&m_{1} m_{2}=-1\end{aligned}$

Since, both slopes are reciprocal of each other.

Therefore, the lines are perpendicular.

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1 year ago

I am really bad at math. What is AC?

kotykmax [81]

The line from a to c

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3 years ago

Read 2 more answers

Richard has just been given an l0-question multiple-choice quiz in his history class. Each question has five answers, of which o

myrzilka [38]

Answer:

a) 0.0000001024 probability that he will answer all questions correctly.

b) 0.1074 = 10.74% probability that he will answer all questions incorrectly

c) 0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

d) 0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he answers it correctly, or he does not. The probability of answering a question correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Each question has five answers, of which only one is correct

This means that the probability of correctly answering a question guessing is $p = \frac{1}{5} = 0.2$

10 questions.

This means that $n = 10$

A) What is the probability that he will answer all questions correctly?

This is $P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} = 0.0000001024$

0.0000001024 probability that he will answer all questions correctly.

B) What is the probability that he will answer all questions incorrectly?

None correctly, so $P(X = 0)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074$

0.1074 = 10.74% probability that he will answer all questions incorrectly

C) What is the probability that he will answer at least one of the questions correctly?

This is

$P(X \geq 1) = 1 - P(X = 0)$

Since $P(X = 0) = 0.1074$ , from item b.

$P(X \geq 1) = 1 - 0.1074 = 0.8926$

0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

D) What is the probability that Richard will answer at least half the questions correctly?

This is

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{10,5}.(0.2)^{5}.(0.8)^{5} = 0.0264$

$P(X = 6) = C_{10,6}.(0.2)^{6}.(0.8)^{4} = 0.0055$

$P(X = 7) = C_{10,7}.(0.2)^{7}.(0.8)^{3} = 0.0008$

$P(X = 8) = C_{10,8}.(0.2)^{8}.(0.8)^{2} = 0.0001$

$P(X = 9) = C_{10,9}.(0.2)^{9}.(0.8)^{1} \approx 0$

$P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} \approx 0$

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0264 + 0.0055 + 0.0008 + 0.0001 + 0 + 0 = 0.0328$

0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

8 0

3 years ago

What is 75.4 in expanded form

Shalnov [3]

Answer: 75.4 =

+ 5

+ 0.4

Step-by-step explanation:

Hope this helps :)

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3 years ago