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3 years ago

6

An item is regularly priced at 60 . It is on sale for 40 percent off the regular price. How much (in dollars) is discounted from

the regular price?

1 answer:

UkoKoshka [18]3 years ago

3 0

Answer:

24.00

Step-by-step explanation:

You might be interested in

What is the length of LN?

nlexa [21]

Find the length of MN by setting up a ratio:

Let MN = X

X/18 = 5/6

Cross Multiply:

6x = 90

Divide both sides by 6:

x = 15

Now you know MN add it to LM for the total length of LN:

15 + 5 = 20

8 0

3 years ago

The amount of potato chips an 18-ounce bag contains follows a normal distribution with a mean of 18.5 ounces and a standard devi

bekas [8.4K]

Answer:

100% probability that the sample mean weight of these 100 bags is less than 18.6 ounces

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 18.5, \sigma = 0.2, n = 100, s = \frac{0.2}{\sqrt{100}} = 0.02$

What is the probability that the sample mean weight of these 100 bags is less than 18.6 ounces

This is the pvalue of Z when X = 18.6. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{18.6 - 18.5}{0.02}$

$Z = 5$ has a pvalue of 1

100% probability that the sample mean weight of these 100 bags is less than 18.6 ounces

7 0

3 years ago

State the domain of each function using interval notation<br> pls show ur work!!

Serggg [28]

Answer:

(-∞ , -6] ∪ [6 , +∞)

Step-by-step explanation:

<u>Let D be the domain of f </u>.

D = {x ∈ IR ; where x² - 36 ≥ 0}

x² - 36 ≥ 0

⇔ x² ≥ 36

⇔ x² ≥ 6²

⇔ √(x²) ≥ √(6²)

⇔ |x| ≥ 6

⇔ x ∈ (-∞ , -6] ∪ [6 , +∞)

5 0

2 years ago

Natalka [10]

Answer:

7

Step-by-step explanation:

the median is the number in the middle of a sorted array

here it has 10 numbers, so the median will be the average of the 5th and the 6th number

the 5th number is 7 and the 6th number is 7

the average is (7+7)/2 = 7

so the median is 7

4 0

2 years ago

How do I solve this out??

GuDViN [60]

<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

$\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]$

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

$\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]$

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0

3 years ago