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3 years ago

6

An item is regularly priced at 60 . It is on sale for 40 percent off the regular price. How much (in dollars) is discounted from

the regular price?

1 answer:

UkoKoshka [18]3 years ago

3 0

Answer:

24.00

Step-by-step explanation:

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Help? :3 Tysm if you do xD

Montano1993 [528]

The answer is A because 13 times 6 equals 78

8 0

3 years ago

What’s the answer????

Bond [772]

First option. The inequality can be split into two separate inequalities.

6 0

3 years ago

The Bengals begin with a possession on their own 27-yard line. Four plays result in the following: gain of 6, loss of 12, a gain

WARRIOR [948]

Answer:

The final position of the ball is on the 16 yard line.

Step-by-step explanation:

The final position of the ball after the fourth play is given by the initial position, in this case the 27-yard line, followed by a succession of sums and subtractions depending on the outcome of each play. For gains we sum and for losses we subtract. So we have:

final position = 27 + 6 - 12 + 2 -7

final position = 27 - 11

final position = 16

The final position of the ball is on the 16 yard line.

7 0

3 years ago

Hii can someone help with this pls :)

BlackZzzverrR [31]

Answer:

$R(x,y) = (0.8,-1.2)$

Step-by-step explanation:

The coordinates of QS are:

$Q(x_1,y_1) = (-2,-6)$

$S(x_2,y_2) = (5,6)$

The ratio is represented as:

$R_{m:n} = 2:3$

Required

Find the coordinates of R

The coordinates of R is calculated by:

$R(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})$

Substitute values for m, n, x's and y's

$R(x,y) = (\frac{2 * 5 + 3 * -2}{2+3},\frac{2*6 + 3*-6}{2+3})$

$R(x,y) = (\frac{4}{5},\frac{-6}{5})$

$R(x,y) = (0.8,-1.2)$

<em>None of the options is correct</em>

6 0

2 years ago

Calculate the standard score of the given X value, X=28.3, where μ=26.3 and σ=28.1 and indicate on the curve where z will be loc

zmey [24]

Answer:

Standard score z=0.07

Step-by-step explanation:

The z-score, or standard score, represents an equivalent value for X but in the standard normal distribution, where μ=0 and σ=1.

For X=28.3 in a normal distribution with μ=26.3 and σ=28.1, the standard score can be calculated as:

$z=\dfrac{X-\mu}{\sigma}=\dfrac{28.3-26.3}{28.1}=\dfrac{2}{28.1}=0.07$

This value is 0.07 standard deviations right to the mean.

In the picture attached, we have located the z-score.

5 0

3 years ago