Ask question

Ask question

All categories

3 years ago

12

Sue's ice cream cone has 6 more scoops than Tessa's ice cream cone. Sue's ice cream cone has 9 scoops. How many scoops are on Te

ssa's ice cream cone? scoops

2 answers:

marshall27 [118]3 years ago

5 0

Tessa has 3 scoops on her cone.

9-6=3

aivan3 [116]3 years ago

4 0

Answer:

3

Step-by-step explanation:

9 - 6 = 3

Hope that helped :)

You might be interested in

Tell which congruence postulate or theorem you would use to show that thetriangles are congruent.

vlabodo [156]

From the given figure, we know that:

$\begin{gathered} NO\cong LO \\ NM\cong LM \\ MO\cong MO \end{gathered}$

This means that the three sides of triangle MNO are congruent to three sides of triangle LMO. Therefore, the triangles are congruent by Side Side Side postulate.

3 0

1 year ago

P=2a+2b, solve for b

Serggg [28]

Answer:

answer in in the photo with a explanation

8 0

3 years ago

10(2^×) + 7(3^×) = 6^× + 70

Mkey [24]

Answer:

x = 2.81 and 2.096

Step-by-step explanation:

Given the expression

10(2^x) + 7(3^x) = 6^x + 70

This can also be expressed as;

10(2^x) + 7(3^x) = (2*3)^x + 70

10(2^x) + 7(3^x) = 2^x*3^x + 70

Let a = 2^x and b = 3^x

10a + 7b = ab + 70

10a + 7b - ab = 70

10a-ab + 7b - 70 = 0

a(10-b)+7(b-10) = 0

a(10-b)-7(10-b) = 0

a-7 = 0 and 10-b = 0

a = 7 and b = 10

Since a = 2^x

7 = 2^x

log 7 = log2^x

log7 = xlog2

x = log7/log2

x = 2.81

Similarly

10 = 3^x

log 10 = log 3^x

log 10 = xlog3

x = log 10/log 3

x = 1/0.4771

x = 2.096

Hence the values of x that satisfies the equation are 2.81 and 2.096

8 0

3 years ago

A landscaper has 10 2/5 cubic yards of peat moss in a truck. If he unloads 2 2/3 cubic yards at the first site and 2 1/4 cubic y

Vikentia [17]

Step-by-step explanation:

The problem bothers on fractions, here we are being presented with mixed fractions.

what we are going to do bascially is to subtract the sum of all the uloaded

peat moss in sites 1 and 2 to get from the peat moss to get the remaining for the third site

therefore

$10\frac{2}{5}-(2\frac{2}{3}+ 2\frac{1}{4})$

we then have to convert the mixed fraction to further simplify the problem we have

$\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})$

we then solve the fraction to the right of the negative symbol first

$=\frac{52}{5}-(\frac{8}{3}+ \frac{9}{4})\\\\=\frac{52}{5}-\frac{32+27}{12} \\\\=\frac{52}{5}-\frac{59}{12} \\\\\=\frac{624-295}{60} \\\\=\frac{329}{60}$

We can now convert to mixed fraction

$=\frac{329}{60}\\\\ =5\frac{12}{25}$

For the third site the remainder is 5 12/25

8 0

3 years ago

If tan theta = 12/5 and cos theta < 0, what is sin theta ?

Talja [164]

1 + tan ² Ф=sec²Ф
1+(12/5)²=sec²Ф
169/25=sec² Ф
sec Ф=⁺₋√(169/25)=⁺₋13/5

sec Ф=1/cos Ф ⇒cosФ=1/sec Ф
cos Ф>0 ⇔ sec Ф>0 ⇔ sec Ф=+ 13/5

cos Ф=1/secФ
cos Ф=1 / 13/5=5/13

we can calculate the sin Ф, with this method.
sin²Ф + cos²Ф=1 ⇒ sin Ф=⁺₋√(1-cos² Ф)
sin Ф=⁺₋√[1-(5/13)²]=⁺₋12/13
like cos Ф>0 and tan Ф>0 ⇒ sin Ф>0 ⇒sin Ф=12/13

answer: d.12/13

other method
tan Ф=sin Ф / cos Ф
12/5=sin Ф / 5/13
sin Ф=(12/5)*(5/13)=12/13

answer: d.12/13

8 0

3 years ago