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fredd [130]
3 years ago
13

You have 30,016 grams of radioactive kind of

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
4 0

Answer:

15,008 grams

Step-by-step explanation:

You have 30,016 grams of radioactive kind of rubidium. How much will be left after 54 minutes if its half-life is 18 minutes? 15,008 grams.

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If point C is not located between points A and B, then AC + CB= AB
Naddik [55]

The location  AC + CB  is  mathematically given as

AC + CB= AB

This is further explained below.

<h3>What is the location  AC + CB of  AB ?</h3>

Because point C can be seen to be in between A and point B, the equation AC + CB must equal AB.

It is important to keep in mind that point C may be located in any part of the space between A and B; yet, the solution will still be considered to be AB in this scenario.

Again, AC + CB = AB.

In conclusion, By way of deduction: if point C is located between points A and B, then it follows that point C is situated on line AB conversely, if point C is not situated on line AB, then it cannot be located between points A and B. As a result, you are able to deduce that AB is a line and that point C is situated on it in the middle of points A and B.

Read more about location  

brainly.com/question/11718756

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3 0
2 years ago
A=1/2b and 3b:4c, find a:c<br> Can anyone help?
Hitman42 [59]

Answer:

3a: 2c

Step-by-step explanation:

a= \frac{1}{2}b \\2a= b\\\\

6a = 3b\\3b : 4c \\6a :4c\\\\=\\3a : 2c

6 0
3 years ago
A cylinder has a volume of 225π inches3 . What is its height, if its radius is 10 inches?
AnnZ [28]

Answer:

The answer is A

Step-by-step explanation:

7 0
3 years ago
If the nth term of a number sequence is n’ – 3,<br> find the first 3 terms and the 10th term.
Diano4ka-milaya [45]

Answer:

First 3 terms: -2, -1, 0

10th term: 7

Step-by-step explanation:

n = 1,

  • n - 3 = 1 - 3 = -2

n = 2,

  • n - 3 = 2 - 3 = -1

n = 3,

  • n - 3 = 3 - 3 = 0

n = 10,

  • n - 3 = 10 - 3 = 7
5 0
3 years ago
I have no idea how this works, but that's not the point here. I really need help on this algebra problem;
Ulleksa [173]
Basically you want to make the equation so that you have
x>something or x<something so basically solve for x or isolate x so


a+bx>cx-d
try to get all the x's on one side
subtract bx from both sides
a>cx-bx-d
add d to both sides
a+d>cx-bx
undistribute
a+d>(x)(c-b)
divide both sides by (c-b)

tada


so the solution is

\frac{a+d}{c-b}>x or
x<\frac{a+d}{c-b}




4 0
3 years ago
Read 2 more answers
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