Answer:
true.
Explanation:
According to my research on information technology, I can say that based on the information provided within the question the statement is completely true. Procedural programming is a widely used paradigm that basically gives the program a set of routines or specifications, and the program mixes and matches them as they continuously repeat the process. It is used in many areas, including video game development.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
=IF(D3>50; E3; F3) and =IF(A1>60;"Pass";"Fail") are valid IF formulas.
Explanation:
P.S - The exact question is -
To find - Select the correct answer from each drop-down menu. Which IF formulas are valid? _____ and _____ are valid IF formulas.
FIRST BLANK
=IF(D3>50; E3; F3)
=IF(D3>50);( E3; F3)
=IF(10<5;23);("Incorrect")
SECOND BLANK
=IF(A1>60;"Pass";"Fail")
=IF(A1>60); ("Pass"; "Fail")
=IF(A1>60; ("Pass"; "Fail"))
Solution -
An IF structure is built following this pattern:
IF(TEST;IF TRUE;IF FALSE)
So,
The correct option is -
=IF(D3>50; E3; F3) and =IF(A1>60;"Pass";"Fail") are valid IF formulas.
Answer:
There are no statements in the question, so I explained the whole code.
Explanation:
A map consists of key - value pairs. The put method allows you to insert values in the map. The first parameter in the put method is the key, and the second one is the value. Also, the keys must be unique.
For example, map.put("123", "John Smith"); -> key = 123, value = John Smith
Even though the key 123 is set to John Smith at the beginning, it will have the updated value Steve Yao at the end. That is because the keys are unique.
Note that the key 222 also has Steve Yao for the value, that is totally acceptable.
Answer:
/*
Find Largest and Smallest Number in an Array Example
This Java Example shows how to find largest and smallest number in an
array.
*/
public class FindLargestSmallestNumber {
public static void main(String[] args) {
//array of 10 numbers
int numbers[] = new int[]{32,43,53,54,32,65,63,98,43,23};
//assign first element of an array to largest and smallest
int smallest = numbers[0];
int largetst = numbers[0];
for(int i=1; i< numbers.length; i++)
{
if(numbers[i] > largetst)
largetst = numbers[i];
else if (numbers[i] < smallest)
smallest = numbers[i];
}
System.out.println("Largest Number is : " + largetst);
System.out.println("Smallest Number is : " + smallest);
}
}
/*
Output of this program would be
Largest Number is : 98
Smallest Number is : 23
*/
Explanation:
