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2 years ago

Can someone answer these questions please

Mathematics

2 answers:

qwelly [4]2 years ago

3 0

length- 9
width- 12
area-108

likoan [24]2 years ago

3 0

Length 9
Width 12
Area 108

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What is 19.2 * 10^8 minutes in hours? Written in scientific notation form?

Lena [83]

Answer should be 1.85 x 10^18

7 0

3 years ago

The length of time a person takes to decide which shoes to purchase is normally distributed with a mean of 8.21 minutes and a st

madam [21]

Answer:

4.55% probability that a randomly selected individual will take less than 5 minutes to select a shoe purchase.

Since Z > -2 and Z < 2, this outcome is not considered unusual.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If $Z \leq 2$ or $Z \geq 2$ , the outcome X is considered to be unusual.

In this question:

$\mu = 8.21, \sigma = 1.9$

Find the probability that a randomly selected individual will take less than 5 minutes to select a shoe purchase.

This is the pvalue of Z when X = 5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5 - 8.21}{1.9}$

$Z = -1.69$

$Z = -1.69$ has a pvalue of 0.0455.

4.55% probability that a randomly selected individual will take less than 5 minutes to select a shoe purchase.

Since Z > -2 and Z < 2, this outcome is not considered unusual.

8 0

2 years ago

Paul wanted to bring his family to the Children’s Museum. There was an exhibit with carnival rides. The tickets for each ride we

Nostrana [21]

We want to define and solve a linear equation to model the given case.

The answers are:

a) x = number of tickets, y = total cost.

b) y = $1.35*x + $6.35

We know that:

The tickets for each ride were $1.35 per ticket.

Paul purchased 30 tickets

He spent a total of $46.85 (on tickets and admission)

The cost for the 30 tickets is:

30*$1.35 = $40.50

a) Now we can define two variables:

y = total cost

x = number of tickets

b) the linear equation would be:

y = $1.35*x + P

Where P is the price of admission.

And we know that the total cost for 30 tickets is $46.85, then we have:

$46.85 = $40.50 + P

$46.85 - $40.50 = P = $6.35

So the admission price is $6.35

This means that the linear equation is:

y = $1.35*x + $6.35

c) Brief explanation, we have the variable y that represents the total cost, it is equal to the admission price (which we found) plus $1.35 times the number of tickets bought (x).

If you want to learn more, you can read:

brainly.com/question/13738061

3 0

2 years ago

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam

kogti [31]

Answer:

Advance tickets-$15

Same-day tickets-$20

Step-by-step explanation:

let x be the cost of advance tickets and y cost of same-day tickets:

$x+y=35\ \ \ \ \ \ \ ...i$