Answer:
- f'(1) exists: f'(1) = -2
- f'(0) DNE
Step-by-step explanation:
<h3>a)</h3>
The function is continuous for x > 0 . The derivative is defined on that interval and is equal to ...
f'(x) = -2x . . . . . for x > 0
Then at x = 1, the derivative is ...
f'(1) = -2(1)
f'(1) = -2
__
<h3>b)</h3>
The function has a jump discontinuity at x=0, so the derivative does not exist at that point. A condition for the existence of the derivative is that the function is continuous at the point of interest.
Answer:
2
Step-by-step explanation:
let (-4,0) be (x1,y1) and (-5,3) be (x2,y2)
slop formula = <u>y2-y1</u>
x2-x1
=(3-0)+(-5-(-4))
=3+(-5+4)
=3+(-1)
=3-1
=2
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
- Slope Formula:
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Find points from chart.</em>
Point (39, 36)
Point (40, 29)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:
- Subtract:
- Divide:
Answer:
Look at the graph for help
Step-by-step explanation:
if you need to graph us desmos graphing its free just plug in you cordinates
