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dmitriy555 [2]
3 years ago
5

Triangle A B C is shown. Lines are drawn from each point to the opposite side and intersect at point D. They form line segments

A G, B E, and C F.
In the diagram, which must be true for point D to be an orthocenter?

BE, CF, and AG are angle bisectors.
BE ⊥ AC, AG ⊥ BC, and CF ⊥ AB.
BE bisects AC, CF bisects AB, and AG bisects BC.
BE is a perpendicular bisector of AC, CF is a perpendicular bisector of AB, and AG is a perpendicular bisector of BC.
Mathematics
2 answers:
Mice21 [21]3 years ago
8 0

Answer:

B BE⊥AC, CF ⊥AB

Step-by-step explanation:

on Edge

Klio2033 [76]3 years ago
4 0

<em>b</em>

That is in fact the answer.

You know where I found it.

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