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dmitriy555 [2]
3 years ago
5

Triangle A B C is shown. Lines are drawn from each point to the opposite side and intersect at point D. They form line segments

A G, B E, and C F.
In the diagram, which must be true for point D to be an orthocenter?

BE, CF, and AG are angle bisectors.
BE ⊥ AC, AG ⊥ BC, and CF ⊥ AB.
BE bisects AC, CF bisects AB, and AG bisects BC.
BE is a perpendicular bisector of AC, CF is a perpendicular bisector of AB, and AG is a perpendicular bisector of BC.
Mathematics
2 answers:
Mice21 [21]3 years ago
8 0

Answer:

B BE⊥AC, CF ⊥AB

Step-by-step explanation:

on Edge

Klio2033 [76]3 years ago
4 0

<em>b</em>

That is in fact the answer.

You know where I found it.

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olchik [2.2K]
The correct answer is:  [B]:  " 25 a²⁵ b²⁵ " .
_________________________________________________________
<span>Explanation:
_________________________________________________________
Given the expression: 
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       </span>→  " (−5a⁵b⁵)² (a³b³)⁵  " ;   Simplify.
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Let us being by examining:
______________________________________
       →    "(−5a⁵b⁵)² " . 

→  "(−5a⁵b⁵)²  = (-5)² * (a⁵)² * (b⁵)²  = (-5)(-5) * a⁽⁵ˣ²⁾ * b⁽⁵ˣ²⁾  = 25a⁽¹⁰⁾b⁽¹⁰⁾ ;

{Note the following properties of exponents:
    (xy)ⁿ = xⁿ * yⁿ ; 

    (xᵃ)ᵇ = x⁽ᵃ * ᵇ) ; 

    (xᵃ) * (xᵇ) = x⁽ᵃ ⁺ ᵇ⁾ .}.
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Then, we examine:
______________________________________
      →    "(a³b³)⁵ " .

→  "(a³b³)⁵ = a⁽³ˣ⁵⁾b⁽³ˣ⁵⁾ = a⁽¹⁵⁾b⁽¹⁵⁾ .
______________________________________

So:   " (−5a⁵b⁵)² (a³b³)⁵ = (-5)a⁽¹⁰⁾b⁽¹⁰⁾ * a⁽¹⁵⁾b⁽¹⁵⁾  " ; 
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Now, we simplify:

          →  " 25a⁽¹⁰⁾b⁽¹⁰⁾ * a⁽¹⁵⁾b⁽¹⁵⁾ " ; 

→  " 25a⁽¹⁰⁾b⁽¹⁰⁾ * a⁽¹⁵⁾b⁽¹⁵⁾ ;
 
               =  25a⁽¹⁰⁾ a⁽¹⁵⁾b⁽¹⁰⁾ b⁽¹⁵⁾  ;

               =  25a⁽¹⁰ ⁺¹⁵⁾ b⁽¹⁰⁺¹⁵⁾ ;

               =  25a⁽²⁵⁾ b⁽²⁵⁾ ; 
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  →  which is:  Answer choice:  [B]:  " 25 a²⁵ b²⁵ " .
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