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vodomira [7]
2 years ago
10

How many outer-shell d electrons are there in each of the transition-metal ions?Mn(IV) :Co(III) :Fe(II) :Ni(II) :

Chemistry
1 answer:
Luden [163]2 years ago
4 0

Answer:

<u>Mn(IV)</u>: 3 outer-shell d electrons

<u>Co(III)</u>: 6 outer-shell d electrons

<u>Fe(II)</u>: 6 outer-shell d electrons

<u>Ni(II)</u>: 8 outer-shell d electrons

Explanation:

<u>Mn(IV)</u>:

The ion is Mn⁴⁺, so it has lost 4 valence electrons. The ground state electronic configuration of Mn is [Ar]3d ⁵ 4s ². When the neutral atom loses 4 electrons, the electronic configuration is [Ar]3d ³.

outer-shell d electrons = 3

<u>Co(III):</u>

The ion is Co³⁺, so it has lost 3 valence electrons. The ground state electronic configuration of Co is [Ar]3d ⁷4s ². When the neutral atom loses 3 electrons, the electronic configuration is [Ar]3d ⁶.

outer-shell d electrons = 6

<u>Fe(II):</u>

The ion is Fe²⁺, so it has lost 2 valence electrons. The ground state electronic configuration of Fe is [Ar]3d ⁶4s ². When the neutral atom loses 2 electrons, the electronic configuration is [Ar]3d ⁶.

outer-shell d electrons = 6

<u>Ni(II):</u>

The ion is Ni²⁺, so it has lost 2 valence electrons. The ground state electronic configuration of Ni is [Ar]3d ⁸4s ². When the neutral atom loses 2 electrons, the electronic configuration is [Ar]3d ⁸.

outer-shell d electrons = 8

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