The residential end-use sector has the largest seasonal variance, with significant spikes in demand every summer and winter. Virtually all homes that have air conditioning use electricity as the main source of cooling in the summer, while winter heating needs are met by a variety of fuels. Some homes use electric resistance heating and electric heat pumps, but even homes with other heating fuels such as natural gas or fuel oil still use some electricity to power furnace fans, boiler circulation pumps, and compressors.
The commercial sector experiences less variance in electricity use, although it shows a noticeable increase in the summer and a slight increase in the winter. Compared to the residential sector, a smaller portion of commercial sector energy consumption is devoted to heating, cooling, and ventilation. However, other energy fuels beyond electricity can be used in the commercial sector to meet both heating and cooling needs. For example, some commercial buildings use natural gas-fired chillers for cooling.
The industrial sector's demand for electricity is relatively flat (with just a slight increase in the summer) because a much smaller portion of its energy consumption (electric and otherwise) is used for heating and cooling. Economic variables generally play a larger role in industrial energy use than weather-related factors. However, seasonal changes can affect industrial activity. For example, in the refining industry, different seasonal slates of petroleum products as well as different seasonal processes may affect electricity needs.
This substance most likely is an inert. It is a substance that is not chemically reactive. It does not change its chemical nature in a reaction. It does not <span>easily react with other chemicals. Most of the group 8 gases in the periodic table are classified as inert, due to their having full outer electron shells. </span>
Answer:
![0.15008\ \text{g}](https://tex.z-dn.net/?f=0.15008%5C%20%5Ctext%7Bg%7D)
![3.23\times 10^{21}](https://tex.z-dn.net/?f=3.23%5Ctimes%2010%5E%7B21%7D)
Explanation:
1 mol of nitrogen at STP = 22.4 L = 22400 cc
n = Mol of
= ![\dfrac{120}{22400}=0.00536\ \text{mol}](https://tex.z-dn.net/?f=%5Cdfrac%7B120%7D%7B22400%7D%3D0.00536%5C%20%5Ctext%7Bmol%7D)
M = Molar mass of
= ![28\ \text{g/mol}](https://tex.z-dn.net/?f=28%5C%20%5Ctext%7Bg%2Fmol%7D)
= Avogadro's number = ![6.022\times 10^{23}\ \text{mol}^{-1}](https://tex.z-dn.net/?f=6.022%5Ctimes%2010%5E%7B23%7D%5C%20%5Ctext%7Bmol%7D%5E%7B-1%7D)
Mass of
is
![m=nM\\\Rightarrow m=0.00536\times 28\\\Rightarrow m=0.15008\ \text{g}](https://tex.z-dn.net/?f=m%3DnM%5C%5C%5CRightarrow%20m%3D0.00536%5Ctimes%2028%5C%5C%5CRightarrow%20m%3D0.15008%5C%20%5Ctext%7Bg%7D)
Mass of the nitrogen is ![0.15008\ \text{g}](https://tex.z-dn.net/?f=0.15008%5C%20%5Ctext%7Bg%7D)
Number of molecules is given by
![nN_A=0.00536\times 6.022\times 10^{23}=3.23\times 10^{21}\ \text{molecules}](https://tex.z-dn.net/?f=nN_A%3D0.00536%5Ctimes%206.022%5Ctimes%2010%5E%7B23%7D%3D3.23%5Ctimes%2010%5E%7B21%7D%5C%20%5Ctext%7Bmolecules%7D)
The number of molecules present in it are ![3.23\times 10^{21}](https://tex.z-dn.net/?f=3.23%5Ctimes%2010%5E%7B21%7D)
Answer:
A. is the correct point.
Explanation:
This is true because no matter how many mL of water is added, the solution only gets more height; the concentration in everything else stays the same, and water doesn't have any concentration. Very confusing, I know. Good luck!
Answer: A) Water Explanation: Water molecules are polar molecules