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2 years ago

A ----------------- is a repeating pattern of positive and negative ions.

Chemistry

1 answer:

Dennis_Churaev [7]2 years ago

4 0

That would be ionic lattice.

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How long would it take for a car to travel 200km if it has an aventage speed of 55 km/ hr

krek1111 [17]

Answer:

It would take 3.64 hours to travel.

Explanation:

200km with 55 per hour.

200 divided by 55 would equal 3.64.

I am dividing because to solve time would be distance/rate.

I hope this helps! :)

7 0

3 years ago

Read 2 more answers

A student obtains the following data: Mass of empty, dry graduated cylinder: 21.577 g Volume added of NaCl solution: 4.602 mL Ma

klasskru [66]

<u>Answer:</u> The density of NaCl solution is 3.930 g/mL

<u>Explanation:</u>

We are given:

Mass of cylinder, $m_1$ = 21.577 g

Mass of NaCl and cylinder combined, M = 39.664 g

Mass of NaCl, $m_2$ = $(M-m_1)=(39.664-21.577)g=18.087g$

To calculate density of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Mass of NaCl = 18.087 g

Volume of NaCl solution = 4.602 mL

Putting values in above equation, we get:

$\text{Density of NaCl}=\frac{18.087g}{4.602mL}\\\\\text{Density of NaCl}=3.930g/mL$

Hence, the density of NaCl solution is 3.930 g/mL

7 0

2 years ago

Please help thank you (15 points)

dsp73

Answer:

Explanation:

The arrows represent the Earth spinning on its own axis in this picture.

4 0

3 years ago

A hot lump of 30.5 g of iron at an initial temperature of 52.7 °C is placed in 50.0 mL H2O initially at 25.0 °C and allowed to r

slava [35]

Answer:

26.7°C

Explanation:

Using the formula; Q = m × c × ΔT

Where; Q = amount of heat

m = mass

c = specific heat

ΔT = change in temperature

In this question involving iron placed into water, the Qwater = Qiron

For water; m= 50g, c = 4.18 J/g°C, Initial temp= 25°C, final temp=?

For iron; m = 30.5g, c = 0.449J/g°C, Initial temp= 52.7°C, final temp=?

Qwater = -(Qiron)

m × c × ΔT (water) =- {m × c × ΔT (iron)}

50 × 4.18 × (T - 25) = - {30.5 × 0.449 × (T - 52.7)}

209 (T - 25) = - {13.6945 (T - 52.7)}

209T - 5225 = -13.6945T + 721.7

209T + 13.6945T = 5225 + 721.7

222.6945T = 5946.7

T = 5946.7/222.6945

T = 26.7

Hence, the final temperature of water and iron is 26.7°C

8 0

3 years ago

Non-conjugated β, γ-unsaturated ketones, such as 3-cyclohexenone, as in base-catalyzed equilibrium with their α,β-unsaturated is

uranmaximum [27]

Answer:

See the attached file for the structure.

Explanation:

Find attached for the explanation

7 0

3 years ago