The correct question is
<span>Teresa graphs the following 3 equations: y=2x, y=x2+2, and y=2x2. She says that the graph of y=2x will eventually surpass both of the other graphs. Is Teresa correct? Why or why not?
we have that
y=2x
y=x</span>²+2
y=2x²
using a graph tool
see the attached figure
<span>We can affirm the following
</span>the three graphs present the same domain-----> the interval (-∞,∞)
The range of the graph y=2x is the interval (-∞,∞)
The range of the graphs y=x²+2 and y=2x² is the interval [0,∞)
therefore
<span>Teresa is not correct because the graph of y = 2x will not surpass the other two graphs since in the interval of [0, infinite) the three graphs present the same range</span>
Answer:3 * (n + 4) = 93
3n + 12 = 93
Subtract 12 to both sides:
3n = 81
Divide 3 to both sides:
n = 27
Step-by-step explanation:
Answer:
The equation that represents the number of tickets that Josiah can buy with $45.50
3 + 8.50x = 45.50
The number of number of tickets that Josiah can buy with $45.50 is 5 ticketa
Step-by-step explanation:
Let the number of tickets be represented by x
Tickets are $8.50 plus he must play Fangalingo a $3 transaction fee for purchasing the tickets online.
The equation that represents the number of tickets that Josiah can buy with $45.50
$3 + $8.50 × x = $45.50
3 + 8.50x = 45.50
Solving further for x
3 + 8.50x = 45.50
8.50x = 45.50 - 3
8.50x = 42.50
x = 42.50/8.50
x = 5
Hence, the number of number of tickets that Josiah can buy with $45.50 is 5 ticketa
Answer:
14.2 hectares
Step-by-step explanation:
Fund Mexico, monarch butterflies occupied 1.13 hectares one recent winter, and 4.01 hectares the following winter (one year later)
The formula of Geometric growth
(Pt/ Po)^1/t
Where Pt = Size after t years = 4.01 hectares
Po = Initial size = 1.13
t = times = 1
=( 4.01/1.13 )^1/1
= 3.5486725664
Hence, Geometric growth rate = 3.5486725664.
It's size in hectares after another 1 year = Current size in hectares × Geometric growth rate
= 4.01 ×3.5486725664
= 14.230176991 hectares
≈ 14.2
Answe8 times 8 equal 69 and bla ba
Step-by-step explanation: