Answer:
118 i think
Step-by-step explanation:
-2{-7-2[3 squared + 2 to the power of 4]-8÷4}
-2{-7-2{9+16]-2}
-2{-7-50-2}
-2(-59)
118
Dilation refers to a non rigid motion where a figure is transform and its image has the same form but a different size measure.
Dilation is define by the rule (x,y)-- (kx, ky) where k represents the scale factor.
On this exercise is given that a triangle with vertices (-2,1), (8,4), and (3,0) was dilated by a scale factor of four, and it is asked to find the vertices of the image of the triangle after the dilation occurred.
Pre-image Image
(-2,1) -- (-2*4,1*4) -- (-8,4)
(8,4) -- (8*4,4*4) -- (32,16)
(3,0) -- (3*4,0*4) -- (12,0)
The coordinates representing the vertices of the triangle's image are (-8,4), (32,16), and (12,0); meaning that the ordered pair which is not a coordinate for a point in the triangle's image is (2,1).
Hello there!
To find the increasing intervals for this graph just based on the equation, we should find the turning points first.
Take the derivative of f(x)...
f(x)=-x²+3x+8
f'(x)=-2x+3
Set f'(x) equal to 0...
0=-2x+3
-3=-2x
3/2=x
This means that the x-value of our turning point is 3/2. Now we need to analyze the equation to figure out the end behavior of this graph as x approaches infinity and negative infinity.
Since the leading coefficient is -1, as x approaches ∞, f(x) approaches -∞ Because the exponent of the leading term is even, the end behavior of f(x) as x approaches -∞ is also -∞.
This means that the interval by which this parabola is increasing is...
(-∞,3/2)
PLEASE DON'T include 3/2 on the increasing interval because it's a turning point. The slope of the tangent line to the turning point is 0 so the graph isn't increasing OR decreasing at this point.
I really hope this helps!
Best wishes :)
