The answer is 12/32 i believe.
        
             
        
        
        
58 should be the answer for the perimeter
        
                    
             
        
        
        
There are 12 ways he can pay this amount using the notes he has the answer is 12.
<h3>What are permutation and combination?</h3>
A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.
Let x be the number of Rs10 notes and y be the Rs20 note
10x + 20y = 220
The whole number of x and y which satisfy the above equation:
x = 0, y =11
x = 2, y =10
x = 4, y =9
x = 6, y =8
x = 8, y =7
x = 10, y =6
x = 12, y =5
x = 14, y =4
x = 16, y =3
x = 18, y =2
x = 20, y =1
x = 22, y =0
Total number of ways = 12
Thus, there are 12 ways he can pay this amount using the notes he has the answer is 12.
Learn more about permutation and combination here:
brainly.com/question/2295036
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Let the lengths of the east and west sides be x and the lengths of the north and south sides be y.  the dimensions you want are therefore x and y.
The cost of the east and west fencing is $4*2*x; the cost of the north and south fencing is $2*2*y.  We have to put in that "2" because there are 2 sides that run from east to west and 2 sides that run from north to south.
The total cost of all this fencing is $4(2)(x) + $2(2)(y) = $128.  Let's reduce this by dividing all three terms by 4:  2x + y = 32.
Now we are to maximize the area of the vegetable patch, subject to the constraint that 2x + y = 32.  The formula for area is A = L * W.  Solving 2x + y = 32 for y, we get y = -2x + 32.
We can now eliminate y.  The area of the patch is (x)(-2x+32) = A.  We want to maximize A.
If you're in algebra, find the x-coordinate of the vertex of this quadratic equation.  Remember the formula x = -b/(2a)?  Once you have calculated this x, subst. your value into the formula for y:  y= -2x + 32.
Now multiply together your x and y values to obtain the max area of the patch.
If you're in calculus, differentiate A = x(-2x+32) with respect to x and set the derivative equal to zero.  This approach should give you the same x value as before; the corresponding y value will be the same;  y=-2x+32.
Multiply x and y together.  That'll give you the maximum possible area of the garden patch.