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3 years ago

5

Find the ke of a ball with a mass of 0.06 kg moving at 50 m/s.

1 answer:

elena-14-01-66 [18.8K]3 years ago

3 0

$ke = \frac{1}{2} m {v}^{2}$

$ke = \frac{1}{2} 0.06 \times {50}^{2}$
ke = 75 J

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Explanation:

This problem is based on conservation of rotational momentum.

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According to law of conservation of angular momentum

5 x 10⁻³ x v sin60 x .11 x .5 = ( I + mr²)ω , where ω is angular velocity of bullet rod system and ( I + mr²) is moment of inertia of bullet rod system .

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3 years ago

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If the person starts over and moves his hand more quickly the waves will have a

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Answer:

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By using Bernoulli theorem

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$v^2_1+2gh_1=v^2_2+2gh_2$

$A_1v_1=A_2v_2$

$v_1=\frac{A_2v_2}{A_1}$

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$v_2=3.038 m/s$

Volume flow rate = $A_2v_2$

Volume flow rate = $\pi r^2_2v_2=\pi (0.042)^2\times 3.038=0.0168 m^3/s$

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3 years ago