Ask question

Ask question

All categories

3 years ago

8

A typical wall outlet in the United States provides a voltage of 120 V to your appliances. What current would be necessary for t

he electricity to pass through a 8-ohm resistor ? Amps

1 answer:

IgorC [24]3 years ago

3 0

Answer:15 Amps

Explanation:

CK12 said it was right

You might be interested in

What is the acceleration of the motorcycle in section CD?

jenyasd209 [6]

Answer:

30m/s²

Explanation:

The acceleration of the motorcycle in section CD is the slope of the velocity - time graph.

Given that;

Initial velocity = 20m/s Time = 6s

Final velocity = 50m/s Time = 7s

The time interval = 7s - 6s = 1s

So;

Acceleration = $\frac{Change in velocity }{time}$ = $\frac{50 - 20}{1}$ = 30m/s²

6 0

3 years ago

An object pulled to the right by two forces has an acceleration of 2.5m/s2. The free-body diagram shows the forces acting on the

Vanyuwa [196]

Answer:

490 N is the correct answer.

Explanation:

8 0

3 years ago

A ball rolls off a desk at a speed of 2 m/s and lands 0.50 seconds later.

Hoochie [10]

Answer:

(a) The ball lands <u>1 m</u> ahead of the desk's base.

(b) The height of the desk is <u>1.225 m.</u>

Explanation:

Given:

Initial velocity of the ball is, $u_{0}=2\ m/s$

Time of flight of the ball is, $t=0.50\ s$

(a)

Let the ball fall at a distance of $x$ from the base of the desk and let the height of the desk be $y$ .

The given motion of the ball is a projectile motion that can be divided into 2 mutually perpendicular directions.

Now, considering only the horizontal motion of the ball. The ball not under the influence of any force in the horizontal direction.

Therefore, the distance covered by the ball horizontally is given as:

$x=v_0\times t\\x=2\times 0.50=1\ m$

So, the ball lands 1 m ahead of the desk's base.

(b)

Now, consider only the vertical motion of the ball. The ball is under the influence of gravity.

So, vertical distance can be obtained using Newton's equations of motion.

We use the following equation of motion:

$y-y_0=u_{oy}t+\frac{1}{2}gt^2$

Where,

$y_{0}\rightarrow \textrm{initial vertical position of ball}\\u_{oy}\rightarrow \textrm{initial vertical velocity}\\g\rightarrow \textrm{acceleration due to gravity}\\y\rightarrow \textrm{final position of ball vertically}$

Here, as the ball leaves the desk horizontally, initial velocity is only in the horizontal direction and doesn't have any component in the vertical direction. So, $u_{oy}=0\ m/s$

Plug in $y_0=h,y=0,g=-9.8,u_{oy}=0,t=0.5$ . Solve for $h$ .

$0-h=0+\frac{1}{2}(-9.8)(0.5)^2\\-h=-4.9\times 0.25\\h=1.225\ m$

Therefore, the height of the desk is 1.225 m.

6 0

3 years ago

What is called frictional force <br>

baherus [9]

Answer:

<em>Friction, force that resists the sliding or rolling of one solid object over another.</em>

3 0

3 years ago

Read 2 more answers

Two blocks A and B have a weight of 11 lb and 6 lb, respectively. They are resting on the incline for which the coefficients of

Andreas93 [3]

Answer:

the block that starts moving first is block A , fr = 1.625 N , fr = 1.5 N

Explanation:

For this exercise we use Newton's second law, for which we take a reference system with the x axis parallel to the plane and the y axis perpendicular to the plane

X axis

fr- Wₓ = 0

fr = Wₓ

Axis y

N- $W_{y}$ = 0

N = W_{y}

Let's use trigonometry to find the components of the weight

sin θ = Wₓ / W

Cos θ = W_{y} / W

Wₓ = W sin θ

W_{y} = W cos θ

Wₓ = 11 sin θ

W_{y} = 11 cos θ

The equation for friction force is

fr = μ N

We substitute

μ (W cos θ) = W sin θ

μ = tan θ

We can see that the system began to move the angle.

θ = tan⁻¹ μ

So the angles are

Block A θ = tan⁻¹ 0.15

θ = 8.5º

Block B θ = tan⁻¹ 0.26

θ = 14.6º

So the block that starts moving first is block A

The friction force is

Block A

fr = Wx = W sin θ

fr = 11 sin 8.5

fr = 1.625 N

Block B

fr = 6 sin 14.6

fr = 1.5 N

5 0

3 years ago