Question:
A) C6H6
B) CH3CH2CH2CH2CH2COH6
C) NaCl
D) NH3
Answer:
The correct option is;
A) C₆H₆
Explanation:
Heat of fusion = 6.02 kJ/mol
Heat of vaporization =40.8 kJ/mol
Here, we analyze each of the options as follows
A) C₆H₆
Benzene has a melting point of 5.5° C and a boiling point of
80.1 ° C similar to water
Heat of fusion = 9.92 kJ/mol
Heat of vaporization =30.8kJ/mol
B) CH₃CH₂CH₂CH₂CH₂COH₆
The above compound is more likely solid
C) NaCl solid
D) NH₃ melting point = -77.73 °C boiling point = -33.34 °C
Of the above, the compounds the one that closely resembles water is C₆H₆
- The data for the first part of the experiment support the first hypothesis.
- As the force applied to the cart increased, the acceleration of the cart increased.
- Since the increase in the applied force caused the increase in the cart's acceleration, force and acceleration are directly proportional to each other, which is in accordance with Newton's second law.
When we state something about the results on the basis whether the observed data supports the original hypothesis, we say that we are concluding the results.
What is the relationship between force and acceleration based on Newton's 2nd law?
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Learn more about Newton's second law of motion brainly.com/question/13447525
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When the object is at rest, there is a zero net force due the cancellation of the object's weight <em>w</em> with the normal force <em>n</em> of the table pushing up on the object, so that by Newton's second law,
∑ <em>F</em> = <em>n</em> - <em>w</em> = 0 → <em>n</em> = <em>w</em> = <em>mg</em> = 112.5 N ≈ 113 N
where <em>m</em> = 12.5 kg and <em>g</em> = 9.80 m/s².
The minimum force <em>F</em> needed to overcome <u>maximum</u> static friction <em>f</em> and get the object moving is
<em>F</em> > <em>f</em> = 0.50 <em>n</em> = 61.25 N ≈ 61.3 N
which means a push of <em>F</em> = 15 N is not enough the get object moving and so it stays at rest in equilibrium. While the push is being done, the net force on the object is still zero, but now the horizontal push and static friction cancel each other.
So:
(a) Your free body diagram should show the object with 4 forces acting on it as described above. You have to draw it to scale, so whatever length you use for the normal force and weight vectors, the length of the push and static friction vectors should be about 61.3/112.5 ≈ 0.545 ≈ 54.5% as long.
(b) Friction has a magnitude of 15 N because it balances the pushing force.
(c) The object is in equilibrium and not moving, so the acceleration is zero.
Answer:
Dog on the right.
Explanation:
Dog on the left is pulling 10N. The dog on the right is pulling at 12N. So the dog on the right is pulling more. Hope this helps :)))
Burning of gases is one the example of chemical change
