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JulijaS [17]
3 years ago
15

Stoichiometry is based on the law of conservation of

Physics
1 answer:
kotykmax [81]3 years ago
8 0

The principles of stoichiometry are based upon the law of conservation of mass.

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Wan and Nurul sat on a see-saw. The see-saw is imbalanced because Wan’s mass is 45 kg while Nurul’s mass is only 30 kg. Suggest
Alex Ar [27]

We have that the see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

From the Question we are told that

Wan’s mass is M_w=45 kg

Nurul’s mass is M_n= 30 kg.

Generally

The Will be balance when the weight on both sides of the see-saw are equal

M_w=M_n+x

45=30+x

x=45-30

x=15kg

In conclusion

The see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

For more information on this visit

brainly.com/question/22255610

5 0
3 years ago
Help please physics!!!
Hitman42 [59]

Answer:

I think c is the answer.....

6 0
3 years ago
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How do various factors affect climent
Svetllana [295]

Answer:

<u>The factors affecting climate are latitude, altitude, land and water distribution, distance from the sea, distance from the sun, prevailing winds and ocean currents, surface covering the land, volcanism, solar constant sunspots, wind direction and nature of mountain chains, mountain barriers.</u>

6 0
3 years ago
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An experimental 1500-kg car travels at a constant speed of 22 m/s around a circular test track that is 80 m across. What is the
stepladder [879]

Answer:

363000 J or 363 kJ

Explanation:

Because the car is not rotating, it has no rotational kinetic energy. Its kinetic energy is then simply

\frac{1}{2} mv^2 = \frac{1}{2}\times1500\times22^2 = 363000 \text{ J}

8 0
4 years ago
if pete (mass =90.00kg) weighs himself and finds that he weighs 30.0 pounds, how far away from the earth is he?
Svet_ta [14]

Here we know that mass of the person is 90 kg

His weight is given as 30 lbf

so here we can convert it into Newton as we know that

1 lbf = 4.45 N

Now from above conversion

30 lbf = 30 \times 4.45 = 133.45 N

now we can use this to find the gravity at this height

mg = 133.45

90\times g = 133.45

g = 1.49 m/s^2

now we know that with height gravity varies as

g' = g(\frac{R}{R+H})^2

1.49 = 9.8(\frac{6.37\times 10^6}{6.37\times 10^6 + h})^2

h = 1.0 \times 10^7 m

so above is the height from the surface of earth

4 0
3 years ago
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