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Alexus [3.1K]
3 years ago
13

True or false. Sometimes de rodes end up on top of your ger rocks.​

Chemistry
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

False

Explanation:

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Predict which of the following changes will cause the volume of the balloon to increase or decrease assuming that the temperatur
IrinaVladis [17]

Answer:

1. a

2. a

3. b

4. c

Explanation:

The STP is the Standard conditions of Temperature and Pressure, in these conditions, T = 0°C and P = 1 atm. By the ideal gas law,

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

We can observe that pressure and volume are indirect proportional, so when one increase, the other decrease. so:

1. The pressure decreases from 1.15 atm to STP, 1 atm, thus the volume increases.

2. The pressure decreases from STP, 1 atm, to 0.5 atm, thus the volume increases.

3. The pressure increases from STP, 1 atm, to 1.25 atm, thus the volume decreases.

4. The pressure remains constant at 1 atm, thus the volume is unchanged.

7 0
3 years ago
Anybody want to share dark jokes?
Pepsi [2]

Answer:

i laughed at a dead body lowkey

Explanation:.

3 0
3 years ago
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A 100 watt bulb emits monochromatic light of wavelength 400 nm. Calculate the number of photons emitted per second by the bulb.
umka21 [38]

Answer:

f = 7.5 E14 s-1

Explanation:

energy emitted by photon:

  • E = h.c / λ.......(1)
  • E = h.f......(2) Planck-Einstein

∴ λ = (400nm)(m/1 E9 nm) = 4.00 E-7 m

∴ h ( Planck's constant) = 6.626070150 E-34 J.s

∴ c (velocity of light) = 3.00 E8 m/s

∴ f (frequency): photon/s

If (1) = (2):

⇒ f = c / λ = E / h

⇒ f = (3.0 E8 m/s) / ( 4.00 E-7 m) = 7.5 E14 s-1

4 0
3 years ago
Molecules of carbon dioxide are linear. What type of force exists between these molecules?
Ratling [72]

Answer:

D) Van der Waals

Explanation:

Given that the geometry is linear, one finds that the C = O bonds cancel out any polar effects due to the linear geometry ( O = C =  O )and gives the molecule a net dipole of zero. Interactions are therefore dependent upon dispersion forces that are classified as Van der Waal Forces or London Forces.

4 0
4 years ago
What is pOH? ?
Marysya12 [62]
POH= -log[OH-]
I don’t see it on there but that is the answer.
3 0
3 years ago
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