Comment down below for the answer
Answer:
25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2
Explanation:
The balanced equation is
Mg3N2 + 6H2O -> 3Mg(OH)2 + 2NH3
Molecular weight of magnesium nitride = 100.9494 g/mol
Molecular weight of magnesium hydroxide = 58.3197 g/mol
one mole of Mg3N2 produces three moles of 3Mg(OH)2
100.9494 g/mol of Mg3N2 produces 3* 58.3197 g/mol of Mg(OH)2
1 gram of Mg3N2 produces
grams of Mg(OH)2
Or 1.733 grams of Mg(OH)2 will be produced by 1 gram of Mg3N2
25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2
The balanced equation between NaOH and H₂SO₄ is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of moles of NaOH moles reacted = molarity of NaOH x volume
number of NaOH moles = 0.08964 mol/L x 27.86 x 10⁻³ L = 2.497 x 10⁻³ mol
according to molar ratio of 2:1
2 mol of NaOH reacts with 1 mol of H₂SO₄
therefore 2.497 x 10⁻³ mol of NaOH reacts with - 1/2 x 2.497 x 10⁻³ mol of H₂SO₄
number of moles of H₂SO₄ reacted - 1.249 x 10⁻³ mol
Number of H₂SO₄ moles in 34.53 mL - 1.249 x 10⁻³ mol
number of H₂SO₄ moles in 1000 mL - 1.249 x 10⁻³ mol / 34.53 x 10⁻³ L = 0.03617 mol
molarity of H₂SO₄ is 0.03617 M
The 2 represents that it is a double carbon bond
it looks like..
C-C = C-C
