a scale-model mound made of the same materials that make the real hill
Answer:
Qm = -55.8Kj/mole
Explanation:
NaOH(aq) + HNO₃(aq) => NaNO₃(aq) + H₂O(l)
Qm = (mc∆T)water /moles acid
Given => 100ml(0.300M) NaOH(aq) + 100ml(0.300M)HNO₃(aq)
=> 0.03mole NaOH(aq) + 0.03mole HNO₃(aq)
=> 0.03mole NaNO₃(aq) + 0.03mole H₂O(l)
ΔH⁰rxn = [(200ml)(1.00cal/g∙°C)(37 – 35)°C]water / 0.03mole HNO₃
= 13,333 cal/mole x 4.184J/cal = 55,787J/mol = 55.8Kj/mole (exothermic)*
Heat of reactions comes from formation of H-Oxy bonds on formation of water of reaction and heats the 200ml of solvent water from 35⁰C to 37⁰C.
Answer:
Balance molecular equation:
K2CO3(aq) + Sr(NO3)2(aq) → SrCO3(s) + 2KNO3(aq)
Net ionic equation:
CO3∧-2(aq) + Sr∧+2(aq) → SrCO3(s)
Explanation:
Potassium carbonate = K2CO3
Strontium nitrate = Sr(NO3)2
Chemical equation:
K2CO3 + Sr(NO3)2 → SrCO3 + KNO3
Balance chemical equation with physical states:
K2CO3(aq) + Sr(NO3)2(aq) → SrCO3(s) + 2KNO3(aq)
Ionic equation:
2K+(aq) + CO3∧-2(aq) + Sr∧+2(aq) + 2NO∧-3(aq) → SrCO3(s) + 2K+(aq) + 2NO∧-3(aq)
Net ionic equation:
CO3∧-2(aq) + Sr∧+2(aq) → SrCO3(s)
2K+ and 2NO∧-3 ions are spectator ions that's way these are not written in net ionic equation.
Spectator ions:
These are the ions that are present same on both side of chemical reaction and does not effect the equilibrium.
