Answer:
There is a 25.14% probability that the order will not be met during a month.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean \mu and standard deviation
, the zscore of a measure X is given by
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
.
The order will not be met if
. So we find the pvalue of Z when
, and subtract 1 by this value.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{6000 - 4500}{900}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B6000%20-%204500%7D%7B900%7D)
![Z = 1.67](https://tex.z-dn.net/?f=Z%20%3D%201.67)
has a pvalue of 0.7486.
So there is a 1 - 0.7486 = 0.2514 = 25.14% probability that the order will not be met during a month.
Answer:
8
Step-by-step explanation:
g(12) = 5/4(12)-7 = 15-7 = 8
So given x=-1, you can substitute it for x in the second equation.
-8(-1)+y=14
y+8=14
y=6
So the solution is (-1,6)
Answer: Yes.
Step-by-step explanation: No number in the map is paired to two different, distinct numbers.
Answer:yes
Step-by-step explanation: