Question

A basketball player is 7 ft tall. He shoots the ball into the basket and the path of the

Answer 1

Answer:

52

Step-by-step explanation:

Given the the equation h(t) =-$15t^2+ 30t+7$ where t is the time in second

So to find the ball's maximum height we can apply the vertex formula:

t= $\frac{-b}{2a}$  

to find the "x" value of the vertex, then plug that value into the original equation as a substitute for "x".

Standard quadratic form is: $ax^2+bx+c$

=> a=15, b=30 in our given equation

<=> t = $\frac{-30}{2*-15} =1$

When t =-1 we have h(t) = $15*1^2+ 30*1+7$ = 52

So the ball's maximum height is:  52

Hope it will find you well.