According to order of operations rules, exponentiation must be done first. Thus, we have
(3^2)*(3^2) = (9)(9) = 81.
Alternatively, note that there's only one base (3) here, even tho' it shows up more than once. So, 3^2*3^2 = 3^(2+2) = 3^4 = 81.
It has a y intercept of 1 rather than 0.
It is shifted one unit up.
Answer:
f(x) = 2x^2 - 3x + 1
Step-by-step explanation:
The root 1 is associated with the factor (x - 1).
The root 1/2 is associated with the factor (x - 1/2), which in turn is equivalent to (2x -1)
The quadratic in question is f(x) = (x - 1)(2x - 1). To write this in standard form, perform the indicated multiplication:
f(x) = 2x^2 - 2x - x + 1, or f(x) = 2x^2 - 3x + 1
Answer:
7 hundredths
Step-by-step explanation:
add 4 to 6 and take away 3
