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Vinil7 [7]
2 years ago
8

A new drug on the market is known to cure 30% of patients with cervical cancer. If a group of 18 patients is randomly selected,

what is the probability of observing, at most, one patient who will be cured of cervical cancer?
Mathematics
1 answer:
Dima020 [189]2 years ago
5 0

Answer:

Probability cured of cervical cancer =  18C0 (0.30)⁰(0.70)¹⁸ +  18C1(0.30)(0.70)¹⁷

Step-by-step explanation:

Given:

Patients cured = 30% = 0.30

Number of patients (n) = 18

Probability cured of cervical cancer = P(X≤1)

Probability cured of cervical cancer  = P(X=0) + P(X=1)

Probability cured of cervical cancer =  18C0 (0.30)⁰(0.70)¹⁸ +  18C1(0.30)(0.70)¹⁷

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