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irga5000 [103]
3 years ago
14

18

Mathematics
1 answer:
Alla [95]3 years ago
6 0

Answer:

40x30= 1200, 20x15=300, 300/1200= 1/4.

Step-by-step explanation:

You can also visualize it. Imagine a field 40’ long and the boy cut the top 20’ of it but left 20’ of the bottom, he would have cut half of it at this point. Now it’s 30’ wide and he cut the left 15’ of what’s remaining but left the right 15’ uncut. So now there’s a 20’x15’ bottom right corner left uncut. There are 4 sections that are 20’x15’ and he left one out of four uncut, otherwise written as 1/4.

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What is the slope called if zero is on the numerator or top of the fraction?
kow [346]
Slope does not exist. A zero in the numerator means you have a horizontal line.
3 0
3 years ago
At which values of x does the graph of f(x)=x^2-x-2/(x^2-1)(x^2-16) have a vertical asymptote? Check all that apply
pychu [463]

vertical asymptotes: x=-4 , x=1 , x=4

6 0
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Read 2 more answers
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Yuki888 [10]

Step-by-step explanation:

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6 0
3 years ago
Consider the function attached below
Masja [62]

Answer:

2

Step-by-step explanation:

Hello,

x=(fof^{-1})(x)=f(f^{-1}(x))=\sqrt{2f^{-1}(x)}+5\\\sqrt{2f^{-1}(x)} =x-5\\2f^{-1}(x)=(x-5)^2\\f^{-1}(x)=\dfrac{(x-5)^2}{2}

now let's replace x by 7 it comes

f^{-1}(7)=\dfrac{(7-5)^2}{2}=\dfrac{2^2}{2}=2

hope this helps

4 0
3 years ago
Is the relationship shown by the data linear? If so, model the data with an equation. X:1,5,9,13 Y:5,10,15,20
ryzh [129]
Let
A (x1,y1)-------> (1,5)
B (x2,y2)------> (5,10)
C (x3,y3)------> (9,15)
D (x4,y4)------> (13,20)

find the slope
AB
m=(10-5)/(5-1)-----> m=5/4

find the slope
CB
m=(15-10)/(9-5)-----> m=5/4

find the slope 
DC
m=(20-15)/(13-9)-----> m=5/4

so
<span>the relationship shown is linear
</span>
<span>to model the data with an equation find the equation of a line
</span>with m=5/4 and point A (1,5)
y-y1=m*(x-x1)-----> y-5=(5/4)*(x-1)----> y=1.25x-1.25+5-----> y=1.25x+3.75

the equation to model data is
y=1.25x+3.75

see the attached  figure

3 0
3 years ago
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