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IrinaVladis [17]
3 years ago
9

Help please.................

Mathematics
2 answers:
Xelga [282]3 years ago
8 0
Babahssjsidiurbebrjrjrofoiriejenenene
Artyom0805 [142]3 years ago
5 0
Angle = 1/2(Angle of Longer Arc - Smaller Arc)
Angle = 1/2(175/57)
Angle = 59°
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A rectangle has dimensions of 12 cm long and 10 cm wide what is the area of the rectangle
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The area and the width are known as 60 and 12 respectively. Rearranging that equation above, and plugging the values, one gets the value of the length of the rectangle as 5.

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What are all of the powers of 3 in the range 3 through 1000
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6 0
4 years ago
A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

4 0
3 years ago
PLEASEEEE WILL GIVE BRAINLIEST TO FIRST RIGHT ANSWER!!!!!!!!!!
svlad2 [7]

Answer:

Well to solve this I’m gonna use substitution

So

2x-3y=-14

5x+9y=14

I‘m gonna isolate ”x” on the first equation

So it’ll be

2x-3y=-14

2x=-14+3y

x=-7+1.5y

X is -7+1.5y

Now you can subsitute into other equations to find what Y is worth

So lets use the second equation

5(-1+1.5y) + 9y = 14

Now solve for y which is -2

If you subsitute Y back in an equation you’d get -4 for x

So y = -2

and X= -4

5 0
2 years ago
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