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wel
3 years ago
11

-7x^2+4x+1 help?????????????????????????

Mathematics
2 answers:
Andre45 [30]3 years ago
8 0
-3x+3 that the answer.
Akimi4 [234]3 years ago
3 0
Its already simplified
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Pls help me !!!!!!!!!!!!!!!!!!!!!!!!!!
marysya [2.9K]

Answer:

1. y^12/y^12=1

2. q^15*1/q^15=1

3. (7(123456.789)^4)^0=1

4. 2^2*1/2^5=1/2^3

5 (x^41/y^15)*(y^15/x^41)=1

Step-by-step explanation:

1. when dividing exponents, subtract the exponents. y^12/y^12=y^(12-12)=y^0=1

2. you do the same as #1

3. Any number to the power of 0 is always 1

4. 1/2^3=1/8

5. since the numerator and denominator is the same, the divide to equal 1

Hope I helped

8 0
3 years ago
PLZ HELPPP <br> What is the equation of the line best fit for the following data?
jolli1 [7]

Answer:

Is there a graph for it?

Step-by-step explanation:

^

8 0
4 years ago
Read 2 more answers
The solution set for the inequality - 3 (x - 4) &gt; 6(x - 1), includes 3 as an element. True False
solniwko [45]
Let's plug in x = 3 to find out. So we just replace every copy of x with 3 and simplify both sides

-3(x-4) > 6(x-1)
-3(3-4) > 6(3-1)
-3(-1) > 6(2)
3 > 12

The last inequality 3 > 12 is false. So the first inequality is false when x = 3. So 3 is NOT in the solution set. 
3 0
3 years ago
Read 2 more answers
Which statement is true? Millimeters are larger than centimeters. Millimeters are larger than centimeters. Meters are larger tha
jasenka [17]

Given :

Conditions :

1) Millimetres are larger than centimetres.

2) Meters are larger than kilometres.

3) Millilitres are larger than kilolitres.

4) Kilograms are larger than grams.

To Find :

Which conditions are correct.

Solution :

1) Millimetre is 0.001 m and cm is 0.01 m .

So, option 1 is correct.

2) Kilometer is 1000 m .

So, option 2 is also correct.

3) Millilitres is 0.001 L and kilolitres is 1000 L .

Therefore, this is not correct.

4) Kilogram is 1000 g .

Therefore, this is also correct.

Therefore, option 1 , 2 and 4 are correct.

Hence, this the required solution.

8 0
3 years ago
I need help what is the answer
alukav5142 [94]

Answer:

245

Step-by-step explanation:

To find the value of a function at a specific point you can substitute that point into the equation.

For the function f(x)=\frac{1}{5}(3-x)^{2}, the specific point would be substituted in for every x in the equation.

f(-32)=\frac{1}{5} (3-(-32))^{2}=\frac{1}{5}(35)^{2}=\frac{1225}{5}=245

8 0
3 years ago
Read 2 more answers
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