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qaws [65]
3 years ago
8

A shipping container is in the shape of a right rectangular prism with a length of 10

Mathematics
1 answer:
sammy [17]3 years ago
3 0

Answer:

224 lbs

Step-by-step explanation:

V = xyz = 10(14)(2) = 280 ft³

280(0.8) = 224

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If 64 feet of rope weighs 20 pounds how much will 80 feet of the same type of rope weigh?​
worty [1.4K]

Answer:

25 pounds, hope its right

Step-by-step explanation

7 0
3 years ago
Please help me need help me please please help me
Reil [10]

9514 1404 393

Answer:

  (3)  y = (x -3)²

Step-by-step explanation:

Try the first value of x in each function:

  (1)  y = 3² -3 ≠ 0

  (2)  y = (3 +3)² ≠ 0

  (3)  y = (3 -3)² = 0 . . . . . . matches the table value for f(3)

  (4)  y = 3² +3 ≠ 0

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The only viable choice is (3).

5 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Helppppppppppppppppppppppppp
Akimi4 [234]
1. x <= 31
2. x < 28

For number 1, x is less than or equal to 31 because the number of days in a month (represented by x) will be less than or equal to 31.

For number 2, x is less than 28 because the number of students (represented by x) in each class will always be less than 28.
7 0
3 years ago
A piece of fabric is 2 yards long. The fabric is cut into 24 pieces of equal length. How long is each piece?
Vera_Pavlovna [14]

Answer:

48 Yards long

Step-by-step explanation: You multiply 24x 2

3 0
3 years ago
Read 2 more answers
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