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Arada [10]
3 years ago
7

A box contains 5 red and 10 white marbles. If 8 marbles are to be chosen at random (without replacement), determine the probabil

ity that (a) 4 will be red, (b) all will be white, (c) at least one will be red.
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

a) 0.0023

b) 0.007

c) 0.993

Step-by-step explanation:

The total number of marbles are;

5 + 10 = 15

Probability of red = 5/15

Probability of white = 8/15

Probability of 4 being red means, 4 will be white too;

Thus, the probability without replacement will be;

5/15 * 4/14 * 3/13 * 2/12 * 10/11 * 9/10 * 8/9 * 7/8 =

0.002331002331 which is approximately 0.0023

b. All white

Here, we have all the marbles selected being white

Thus the probability without replacement will be;

10/15 * 9/14 * 8/13 * 7/12 * 6/11 * 5/10 * 4/9 * 3/8

= 0.006993006993 which is approximately 0.007

c. At least one will be red

Mathematically, that will be;

1 - p(no red)

p(no red) = p(all white)

P(all white) = 0.007

hence P(no red) = 0.007

P(at least one red) = 1 - 0.007 = 0.993

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Answer:

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Step-by-step explanation:

If there is a relationship of direct proportionality for every ordered pair of the table, then the constant of proportionality must the same for every ordered pair. The constant of proportionality (k) is described by the following expression:

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Where:

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y - Output.

If we know that (x_{1}, y_{1}) = (13, 45.5), (x_{2}, y_{2}) = (14, 49) and (x_{3}, y_{3}) = (15, 52.5), then the constants of proportionalities of each ordered pair are, respectively:

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k_{2} = \frac{7}{2}

k_{3} = \frac{y_{3}}{x_{3}}

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k_{3} = \frac{7}{2}

Since k_{1} = k_{2} = k_{3}, the constant of proportionality is 3.5.

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