Answer:
what was the investigation ???
You have to use this knwoledge:
1) The superscript number on the left of the symbol is the mass number (A)
2) The underscript number on the left of the symbol is the atomic number (Z)
3) The atomic number, Z, is the number of protons of the atom.
4) The number of electrons of an atoms is equal to the number of protons.
5) The mass number, A is equal to the number of neutrons, N, plus the number of protons, Z, i.e. A = N + Z, from which you obtain N = A - Z
Now I am going to apply above rules to solve the three cases for you.
I will use other notation just because the editor does not permit to place superscripts and underscripts on the left of the symbol.
a) 62 Cu 29 and 62 Zn 39
62 Cu 29:
Z = 29 = number of protons
A = 62 = N + Z => N = 62 - Z = 62 - 29 = 33
Number of electrons = number of protons = 29
62 Zn 39:
Z = 39 = number of protons
A = 62 = N + Z => N = 62 - Z = 62 - 39 = 23
Number of electrons = number of protons = 39
Answers:
protons are not equal
neutrons are not equal
electrons are not equal.
b) 40Ar18 and 41K19
40Ar18:
Z = 18 = number of protons
A = 40 = N + Z => N = 40 - 18 = 22 = number of neutrons
number of electrons = number of protons 18
41K19:
Z = 19 = number of protons
A = 41 = N + Z> N = 41 - 19 = 22
number of electrons = number of protons = 19
Answers:
protons are not equal
neutrons are equal
electrons are not equal
c) 14N7 and 15N7
14N7:
Z = 7 = number of protons
A = 14 => N = 14 - 7 = 7 = number of neutrons
number of elecfrons = number of protons = 7
15N7:
Z = 7 = number of protons
A = 15 => N = 15 - 7 = 8 = number of neutrons
number of electrons = number of protons = 7
Answers:
protons are equal
neutrons are not equal
electrons are equal
The chemical bonds in CH4 are all single bonds. C only can bond 4 times because it needs 8 electrons in it's outer shell and only has four right now. The bonds represented are all single bonds because there are two electrons present on each side of the carbon. Two electrons, in this case, equals one bond.
Answer:
12.5 g of Li are needed in order toproduce 0.60 moles of Li₃N
Explanation:
The reaction is:
6Li(s) + N₂(g) → 2Li₃N(s)
If nitrogen is in excess, the lithium is the limiting reactant.
Ratio is 2:6
2 moles of nitride were produced by 6 moles of Li
Then, 0.6 moles of nitride were produced by (0.6 .6)/ 2 = 1.8 moles of Li
Let's convert the moles to mass → 1.8 mol . 6.94 g/ 1mol = 12.5 g of Li