Its mass, weight, volume, and density. it also describes odor, texture, shape and hardness hope that helped!
Answer: B) has a small negative value.
Explanation:
Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.
is positive when randomness increases and is negative when randomness decreases.
As there are 5 moles of gaseous reactants and 4 moles of gaseous products, the gaseous molecules are decreasing on moving from reactants to products, thus randomness decreases and is negative.
Thus has a small negative value.
Sodium(Na) is the limiting reagent.
<h3>What is Limiting reagent?</h3>
The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. The precise quantity of reactant required to react with another element may be estimated from the reaction stoichiometry.
How do you identify a limiting reagent?
The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.
Start by writing the balanced chemical equation that describes this reaction
Notice that the reaction consumes 2 moles of sodium metal for every 1 mole of chlorine gas that takes part in the reaction and produces 2 moles of sodium chloride.
now we can see that we have 3 moles of sodium and 3 moles of chlorine, according to question. so, we can say that sodium is the limiting reagent in the given situation.
to learn more about Limiting Reagent go to - brainly.com/question/14222359
#SPJ4
Answer:
1.atomic number
2.electron
3.element
4.atom
5.neutron
6.nucleus
7.proton
Explanation:
please like and Mark as brainliest
Answer:
17g
Explanation:
4NH3 (g) + 502 (g) –> 4NO (g) + 6H20 (g)
Mass of O2 mole = 32g
Therefore 5O2 = 160g
Mass of NH3 mole = 17g
Therefore 4NH3 = 17 x 4 =68g
Required amount of NH3 = 68 x 40/160 = 17g