Answer:
Step-by-step explanation:
22) J(2,-1); K(2,5)
Distance = √(x₂-x₁)² + (y₂-y₁)²
= √( 2- 2)² + (5 - [-1] )²
= √0 + (5 + 1 )²
=√ ( 6 )² = 6
25) A(0,3) ; B (0,12)
distance =√(0-0)² + (12 - 3 )²
=√( 9)² = 9
28) Q(12,-12) ; T(5,12)
distance = √(5 - 12)² + (12 - [-12] )²
= √( -7)² + (12 + 12] )²
= √ 49 + (24)²
= √ 49 + 576
= √625
=25
Answer:
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.
Step-by-step explanation:
given that Ty and Gajge are football players.
Carries is 15 for both and average is the same 4 for both.
But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.
Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)
But for Gajge, highest is 19 and lowest is 2.
i.e. range = 19-2 =17 very much higher than that of Ty
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.
Answer:
627200LJ
Step-by-step explanation:
Height of box=5 m
Side of square base=4 m
Volume of rectangular box=
Using the formula
Volume of rectangular box=
Density of material=
We know that
Using the formula
Mass of rectangular box=
Gravity=
Weight of rectangular box,F=
Let L be the vertical distance traveled by box
Total work done =
Therefore,total work done against gravity =
=627200 L J
Hence, the box requires work against gravity=627200LJ
Answer: 3
Step-by-step explanation: QPEX VERIFIED JUST DID IT
You can tell if the equation is linear or not if the equation makes a straight line on a graph.
