All categories

3 years ago

Multiply. x + 4x + 2 2x2 + 3x – 4

Mathematics

1 answer:

Yuliya22 [10]3 years ago

7 0

Answer:

I think question is:

(x+4x+2)(2x^2+3x-4)

:(5x+2)(2x^2+3x-4)

5x(2x^2+3x-4)+2(2x^2+3x-4)

10x^3+15x^2-20x+4x^2+6x-8

10x^3+19x^2-14x-8

You might be interested in

Solve the system 5x+3y=-9 & -2+y=8

Illusion [34]

X=-39/5 and y=10 :) i hope this helps you out !

5 0

3 years ago

Please answer the question from the attachment.

xenn [34]

Change it into improper fraction to make it easier or just solve it as is.
= $3\frac{5}{8}$ - $2\frac{7}{8}$
= $\frac{29}{8}$ - $\frac{23}{8}$
= $\frac{6}{8}$ = $\frac{3}{4}$
OR
= $3 \frac{5}{8}$ - $2 \frac{7}{8}$
divide it to two parts:
3-2=1 and $\frac{5}{8}$ - $\frac{7}{8}$ = $\frac{-2}{8}$
$1\frac{-2}{8}$ ⇒(1×8-2=6)
= $\frac{6}{8}$ = $\frac{3}{4}$

6 0

3 years ago

Plzz help!!!!<br><br> Which set of ordered pairs corresponds to the graph?

adelina 88 [10]

Answer:

Option 3rd is correct

Step-by-step explanation:

(1,-6),(2,-4),(2,-2),(4,-2),(6,0)

5 0

3 years ago

Read 2 more answers

Solve the inequality.

Karolina [17]

The answer is c.g>-7

6 0

3 years ago

Rex took out a loan for $5000 and planned to pay it back in 4 years. If he paid $600 in interest for those 4 years, what was the

Gwar [14]

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$600\\ P=\textit{original amount deposited}\dotfill & \$5000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &4 \end{cases} \\\\\\ 600=5000(\frac{r}{100})(4)\implies \cfrac{600}{5000(4)}=\cfrac{r}{100}\implies \cfrac{3}{100}=\cfrac{r}{100}\implies \boxed{3=r}$

7 0

2 years ago

Multiply. x + 4x + 2 2x2 + 3x – 4​

Multiply. x + 4x + 2 2x2 + 3x – 4