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alexgriva [62]
3 years ago
14

HELP! ITS ABOUT SURVEYSSS EXPLANATION NEEDED

Mathematics
1 answer:
dimaraw [331]3 years ago
3 0

Answer:

B is the correct answer (Check the explanation below)

Step-by-step explanation:

Probability of boys who do play = 1593/2451 = 0.6499 or 64.99% (if you times by 100 to change to percentage)

Probability of boys who do not play =858/2451 = 0.35 or 35%

Probability of girls who do play = 1361/2996 = 0.4542 or 45.42%

Probability of girls who do not play = 1635/2996 = 0.5457 or 54.57%

Probability of boys and girls who play = 2954/5447 = 0.5423 or 54.23%

Probability of boys and girls who do not play = 2493/5447 =0.4577 or 45.77%

you can see the correct statement is

Probability of girls who do play = 1361/2996 = 0.4542 or 45.42%

total number of girls is 2996 and we found out almost 54% do not play and almost 45% play

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I need help please:))
Mariana [72]

Answer:

2x^2

Step-by-step explanation:

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5 0
3 years ago
N - 8 &gt; 5 <br><br> A. n &gt; 13 <br> B. n &gt; 3 <br> C. n &gt; - 3 <br> D. n &gt; -13
statuscvo [17]

the answe is a- n>13

4 0
4 years ago
A helicopter starting on the ground is rising directly
Serggg [28]

Answer:

Oook, quick setup: pick a cartesian plane, be (0;y(t))the position of the helicopter as time passes, and (x(t);0) your position as you start running. In my horrible sketch, the green line is the distance when you start running, the red line is the distance you need,  in general what you want is to move one end of the segment up, the other right, and stretch it.

That distance is easily found with the formula for the distance between two points in the plane, or d=\sqrt{(\Delta x)^2+(\Delta y)^2}= \sqrt{x^2(t)+y^2(t)} (playing a bit with the squares). At this point we need to write down expressions for both x(t), y(t) and find at what value of t we need to evaluate our distance.

For the sake of semplicity, let's start measuring times the moment you start running. Since speed is constant, both expressions will be of the form s=vt+s_0

The equation for the runner becomes simply x(t)=10t, since you haven't moved until the heli is high enough.

The equation of the helicopter is y=25t+30 since the heli is 30ft above ground when you start running.

Finally, we need to know how many seconds have passed when the heli is at 60 ft above ground. that happens when 60=25t+30 \rightarrow t=\frac{30}{25} = 1.20s. in this time, you are at  x(1.2)=10(1.2)=12ft from the origin.

Plugging it in the distance formula you get: \sqrt{12^2+60^2}= \sqrt{144+3600}=4\sqrt {234}\approx 61.2ft

8 0
3 years ago
The O'Brien's are building a rectangular deck around the outside of their circular pool.
Lera25 [3.4K]

A:

Width of the deck = 2x+3 units

Length of the deck = 5x+6 units

So area of rectangular deck = Length * width

= (5x+6)(2x+3)

Area = 10x^{2}+15x+12x+18

Area= 10x^{2}+27x+18 units square

As mentioned in part B, the area of the pool is 3x^{2}+7x+6 so the combined area of the deck and pool is

Area = area of rectangular deck + area of pool

= 13x^{2}+34x+24 unit square


B:

The area of only the deck is 10x^{2}+27x+18 unit square



5 0
3 years ago
The slope of any line perpendicular to , where A(0, -3) and B(4, 9) are two points on the line, is m =
enyata [817]

Answer:

m = -1/3

Step-by-step explanation:

The slope of the line can be calculated using the slope formula.

m = \frac{y_2-y_1}{x_2-x_1} = \frac{9--3}{4-0} = \frac{12}{4} = 3

Since this is the line with points AB, the slope of any line perpendicular to it will be -1/3. All perpendicular lines cross at a 90 degree angle and as such their slopes are the negative reciprocals of each other. This means 3 becomes -1/3.

4 0
3 years ago
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