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2 years ago

HELP! ITS ABOUT SURVEYSSS EXPLANATION NEEDED

Mathematics

1 answer:

dimaraw [331]2 years ago

3 0

Answer:

B is the correct answer (Check the explanation below)

Step-by-step explanation:

Probability of boys who do play = 1593/2451 = 0.6499 or 64.99% (if you times by 100 to change to percentage)

Probability of boys who do not play =858/2451 = 0.35 or 35%

Probability of girls who do play = 1361/2996 = 0.4542 or 45.42%

Probability of girls who do not play = 1635/2996 = 0.5457 or 54.57%

Probability of boys and girls who play = 2954/5447 = 0.5423 or 54.23%

Probability of boys and girls who do not play = 2493/5447 =0.4577 or 45.77%

you can see the correct statement is

Probability of girls who do play = 1361/2996 = 0.4542 or 45.42%

total number of girls is 2996 and we found out almost 54% do not play and almost 45% play

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Substitute the given values into the formula, and solve for the unknown variable.

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Which expression should you simplify to find the 90% confidence interval,

Alex787 [66]

Answer:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

Step-by-step explanation:

The estimated proportion of interest is $\hat p=0.45$

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value is:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the true population proportion is interest is given by this formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Replacing the values provided we got:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

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2 years ago