Answer:
2x^2
Step-by-step explanation:
just took the test
Answer:
Oook, quick setup: pick a cartesian plane, be
the position of the helicopter as time passes, and
your position as you start running. In my horrible sketch, the green line is the distance when you start running, the red line is the distance you need, in general what you want is to move one end of the segment up, the other right, and stretch it.
That distance is easily found with the formula for the distance between two points in the plane, or
(playing a bit with the squares). At this point we need to write down expressions for both
and find at what value of t we need to evaluate our distance.
For the sake of semplicity, let's start measuring times the moment you start running. Since speed is constant, both expressions will be of the form 
The equation for the runner becomes simply
, since you haven't moved until the heli is high enough.
The equation of the helicopter is
since the heli is 30ft above ground when you start running.
Finally, we need to know how many seconds have passed when the heli is at 60 ft above ground. that happens when
. in this time, you are at
from the origin.
Plugging it in the distance formula you get: 
A:
Width of the deck =
units
Length of the deck =
units
So area of rectangular deck = Length * width
= 
Area = 
Area=
units square
As mentioned in part B, the area of the pool is
so the combined area of the deck and pool is
Area = area of rectangular deck + area of pool
=
unit square
B:
The area of only the deck is
unit square
Answer:
m = -1/3
Step-by-step explanation:
The slope of the line can be calculated using the slope formula.

Since this is the line with points AB, the slope of any line perpendicular to it will be -1/3. All perpendicular lines cross at a 90 degree angle and as such their slopes are the negative reciprocals of each other. This means 3 becomes -1/3.